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Pavel [41]
3 years ago
15

Simplify the expression Z^0⋅(Z^2⋅Z^−5)^4 using positive exponents

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0
Jajabhsuababahaisiajnq
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What digits makes 3,71? Divisible by 3 (connections academy unit test)
wlad13 [49]

Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Let us check which digits will make 371? divisible by 3.

3+7+1+0=11

11 is not divisible by 3.

Now let us check other digits as well.

3+7+1+1=12

12 is divisible by 3.

3+7+1+4=15

15 is also divisible by 3.

3+7+1+7=18

18 is divisible by 3 as well.

Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.

6 0
4 years ago
2) How old am I if 500 is reduced by 4 times my age is
kakasveta [241]
Answer:
61 years old

Explanation:
You can solve this using an equation. The equation I’m going to use is:
500 - 4x = 256

x will represent the age we are trying to find, so now we will solve to x.

500 - 4x = 256
(- 500 from both sides of the equation)

-4x = -244
(➗-4 on both sides)

x = 61


brainliest plz? :)
5 0
3 years ago
What is the measurement of PQ?
Sholpan [36]

<em>The measure of PQ is 12.72</em>

<h2>Explanation:</h2>

We have the right triangle ΔPQR and we want to know the measure of PQ. PQ is opposite to ∠R, so from trigonometry we know that:

sin(\alpha)=\frac{Opposite \ side}{Hypotenuse} \\ \\ \\ Here: \\ \\ \alpha=m\angle R=58^{\circ} \\ \\ Opposite \ side=\overline{PQ} \\ \\ Hypotenuse=\overline{RQ}=15 \\ \\ \\ So: \\ \\ sin(58^{\circ})=\frac{\overline{PQ}}{15} \\ \\ \\ Isolating \ \overline{PQ}: \\ \\ \overline{PQ}=15sin(58^{\circ}) \\ \\ \overline{PQ}=15(0.848)\\ \\ \boxed{\overline{PQ}=12.72}

<h2>Learn more:</h2>

Right triangles: brainly.com/question/10252821

#LearnWithBrainly

7 0
4 years ago
A student measures the mass of an 8 cm^3 block of confectioner’s (powdered) sugar to be 4.49 grams. Determine the density of pow
melomori [17]

Answer:

The density of powdered sugar is 0.561 g/cm^3

Step-by-step explanation:

We are given that A student measures the mass of an 8 cm^3 block of confectioner’s (powdered) sugar to be 4.49 grams

Mass of block of confectioner’s (powdered) sugar = 4.49 grams

Volume of block = 8 cubic cm

We are supposed to find  the density of powdered sugar.

So, Density = \frac{Mass}{Volume}

Density = \frac{4.49}{8}

Density =0.561 g/cm^3

Hence the density of powdered sugar is 0.561 g/cm^3

4 0
3 years ago
Please help! I have a barrel of apples. 70% are red and 30% is green but 24% of all green apples are damaged. What is the remain
Assoli18 [71]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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