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Pavel [41]
2 years ago
15

Simplify the expression Z^0⋅(Z^2⋅Z^−5)^4 using positive exponents

Mathematics
1 answer:
Makovka662 [10]2 years ago
5 0
Jajabhsuababahaisiajnq
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Jill arranged her baseball cards in 4 rows of 9 cards then she arranged the cards in 2 rows of 18 cars how many other ways can J
Ronch [10]
She can arrange them in the following;
1 row of 36
2 rows of 18 (doesnt count because it says other and this has already been mentioned)
3 rows of 12
4 rows of 9 (doesnt count because it says other and this has already been mentioned)
6 rows of 6
3 0
2 years ago
Read 2 more answers
2/5;0.5 tell whether each pair shows equivalent number
Georgia [21]
2/5= 40%, so no, they are not equivalent numbers,<span />
4 0
3 years ago
4.9t+0.3=5.6t+0.72 I need help on my work lol
Whitepunk [10]

The first step that we must take before attempting to solve the problem is to understand what the problem is asking us to do and what is given to us to help accomplish that goal.  Although it does not explicitly state that we must solve for t, this is usually what the problem statement would be asking if we just receive and expression like this.  What is given to us to accomplish that goal is the expression 4.9t+0.3=5.6t+0.72.

Now that we have completed that step, we can move onto the next part which is actually solving the problem.  The next step that we should take when solving for the unknown, in this case t, is to subtract 4.9t from both sides.

<u>Subtract 4.9t from both sides</u>

  • 4.9t+0.3=5.6t+0.72
  • (4.9t-4.9t)+0.3=(5.6t-4.9t)+0.72
  • 0.3=(5.6t-4.9t)+0.72
  • 0.3=(0.7t)+0.72

Now that we got all of the t's to one side, let us isolate t completely and the next step that we should take is to subtract 0.72 from both sides.

<u>Subtract 0.72 from both sides</u>

  • 0.3=0.7t+0.72
  • 0.3 - 0.72=0.7t+0.72 - 0.72
  • 0.3 - 0.72=0.7t
  • -0.42=0.7t

The final step that we need to take to isolate t would be to divide both sides by 0.7 which would remove the coefficient from the unknown variable t and divide 0.7 from -0.42

<u>Divide both sides by 0.7</u>

  • -0.42=0.7t
  • \frac{-0.42}{0.7}=\frac{0.7t}{0.7}
  • \frac{-0.42}{0.7}=t
  • -0.6=t

Therefore, after fully narrowing down the solution we were able to determine that the solution of the unknown variable or t is equal to -0.6

5 0
1 year ago
The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an
Naddika [18.5K]

Answer:

the shaded area is 26, the non-shaded area 16

Step-by-step explanation:

The red shaded lines had numbers as well so I add all of them up.

The non-shaded lines didn't have a number, but the bottom had the same length of the top line so therefore your answer is 26 for Shaded, and 16 for non-shaded.

3 0
2 years ago
Read 2 more answers
At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
elixir [45]

Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

5 0
3 years ago
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