4c2 + 7c – 5 = 0 a=4 b=7 c=-5
x = [-b +-sq root (b^2 -4ac)] / 2a
x = [-7 +-sq root(7^2 -4*4*-5)] / 2*4
x = [-7 +-sq root(49 + 80)] / 8
x = [-7 +-5.5677643628] /8
x1 = 0.544727125
x2 = -2.294727125
Answer:
I believe the answer is a imaginary number... I only know the fist one I'm sorry..
Step-by-step explanation:
I think this because a rational number is a number that is real. A Whole number is one without decimals. A natural number is something that is also real. I really hope this is helpful.
j^3
_______
4^2 h^4
when you have negatives, you want them to be positive. To do that you need to convert it into a fraction
Sawyer you please please call the internet
9514 1404 393
Answer:
29
Step-by-step explanation:
From the point where the chords cross, the product of lengths to the circle intercepts is the same for both chords:
LB·LD = LC·LE
10·18 = 9·LE
LE = 180/9 = 20
The the measure of CE is ...
CE = LC +LE = 9 + 20
CE = 29
