Solve the equation 4c2 + 7c – 5 = 0 using the quadratic formula
1 answer:
4c2 + 7c – 5 = 0 a=4 b=7 c=-5
x = [-b +-sq root (b^2 -4ac)] / 2a
x = [-7 +-sq root(7^2 -4*4*-5)] / 2*4
x = [-7 +-sq root(49 + 80)] / 8
x = [-7 +-5.5677643628] /8
x1 = 0.544727125
x2 = -2.294727125
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