Answer:
12.57
Step-by-step explanation:
Answer:
C. H0 : p = 0.8 H 1 : p ≠ 0.8
The test is:_____.
c. two-tailed
The test statistic is:______p ± z (base alpha by 2) ![\sqrt{\frac{pq}{n} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%20%7D)
The p-value is:_____. 0.09887
Based on this we:_____.
B. Reject the null hypothesis.
Step-by-step explanation:
We formulate null and alternative hypotheses as proportion of people who own cats is significantly different than 80%.
H0 : p = 0.8 H 1 : p ≠ 0.8
The alternative hypothesis H1 is that the 80% of the proportion is different and null hypothesis is , it is same.
For a two tailed test for significance level = 0.2 we have critical value ± 1.28.
We have alpha equal to 0.2 for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28
The test statistic is
p ± z (base alpha by 2) ![\sqrt{\frac{pq}{n} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%20%7D)
Where p = 0.8 , q = 1-p= 1-0.8= 0.2
n= 200
Putting the values
0.8 ± 1.28 ![\sqrt{\frac{0.8*0.2}{200} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B0.8%2A0.2%7D%7B200%7D%20%7D)
0.8 ± 0.03620
0.8362, 0.7638
As the calculated value of z lies within the critical region we reject the null hypothesis.
The annual snowfall for city B is 7.7 inches.
Since it is 12.5 inches more: 58.7 - 12.5 = 46.2
Since 46.2 is 6 times that of city B: 46.2 / 6 = 7.7
The mean would be 43006.
To find the mean, you simply add up all of the numbers in the sequence and divide by how many numbers are in the sequence.
43005+43007+43006+43005+43007=215030
215030 / 5 = 43006.