2 years ago

Suppose a triangle has two sides of length 32 and 35, and that the angle

Mathematics

1 answer:

Gennadij [26K]2 years ago

4 0

Answer:

Step-by-step explanation:

It is the law of cos

C^2= A^2+B^2-2*A*B*cosL where L is the angle between A and B

so C = 32^2 + 35^2 - 2(32)(35)cos120°

You might be interested in

What is the interquartile range of the data? 120, 140, 150, 195, 203, 226, 245, 280 235.5

zheka24 [161]

For the first one it's 90.5, I know cause I just took the test and it's right. The second one I'm not sure..

5 0

3 years ago

-6h plus 4 - 3plus h equals 11

olga55 [171]

$- 6h + 4 - 3 + h = 11$
So we start by combining like terms;
$- 6h + h = - 5h$
$4 - 3 = 1$
Now we have;
$- 5h + 1 = 11$
We then subtract 1 from both sides;
$- 5h + 1 = 11$
$- 5h = 10$
Then we divide both sides by 5;
$- 5h = 10$
$- 5h \div - 5h = h$
$10 \div - 5h = - 2$
Leaving the final answer to be h = -2

5 0

3 years ago

I have a test tomorrow, I don't get how my teacher got 3 2/3 not this problem. If you answer, please show your work, so I can se

gogolik [260]

Which problem ,???????

3 0

2 years ago

Read 2 more answers

Complete the equations.

mr_godi [17]

Answer:

Step-by-step explanation: