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3 years ago

6c/3 + t when c =-2 and t=5

Mathematics

1 answer:

tamaranim1 [39]3 years ago

7 0

Answer:

c+1 = 0

Step-by-step explanation:

Polynomial Roots Calculator is a set of methods aimed at finding values of c for which F(c)=0

Rational Roots Test is one of the above - mentioned tools. It would only find Rational Roots that are numbers c which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is -6.

The factor(s) are:

of the Leading Coefficient: 1

of the Trailing Constant: 1,2,3,6

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Tom has 8 toys each toy weighs either 20 grams or 40 grams or 50 grams he has a diffrent number of toys (at least one) of each w

liberstina [14]

Answer:

110

Step-by-step explanation:

He said he had atleast 1 of each. Hope it helps.

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4 years ago

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Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen

vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0

4 years ago

Help im diening please

Alina [70]

Answer:

y = x + 3

Step-by-step explanation:

To know which of the equations represent the relationship between x and y, you need to substitute the x and y values into the equation. If when the equation is solved, the left-hand and right-hand side of the equation equal each other and hence the equation is true, then the equation must be correct in expressing the relationship between the x and y values. If not, then it is not correct.

As this question is only dealing with linear equations, we know that the gradient of the line is constant and hence the rate of change in x and y values is constant. Therefore, we can choose to substitute any of the given combinations of x and y values into the equation to obtain the correct equation. As it is easier to use smaller numbers for smaller calculations, we'll use the first combination of x = 1 and y = 4 .

Equation No. 1 : y = 3x + 1 where x = 1 , y = 4 and x = 2 , y = 5

( 4 ) = 3 ( 1 ) + 1

4 = 4

However, as this equation has a constant not equal to 1 in front of the x variable and hence a different gradient to the other equations, we will substitute the second combination of x and y values.

( 5 ) = 3 ( 2 ) + 1

5 = 6

Therefore, equation is false / incorrect.

Equation No. 2 : y = x + 1 where x = 1 , y = 4

( 4 ) = ( 1 ) + 1

4 = 2

Therefore, equation is false / incorrect.

Equation No. 3 : y = x + 3 where x = 1 , y = 4

( 4 ) = ( 1 ) + 3

4 = 4

Therefore, equation is true / correct.

Equation No. 4 : y = x - 3 where x = 1 , y = 4

( 4 ) = ( 1 ) - 3

4 = - 2

Therefore, equation is false / incorrect.

8 0

3 years ago

solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3(4^-4 over 3^3)*3^3 Pleas

Jobisdone [24]

Answer:

$3^64^{11}$

Step-by-step explanation:

It appears you're trying to simplify ...

$(3^{-2}4^{-5}5^0)^{-3}\cdot\dfrac{4^{-4}}{3^3}\cdot 3^3$

The final factor cancels the denominator of the fraction, so we have ...

$3^{(-2)(-3)}4^{(-5)(-3)-4}=3^64^{11}$

_____

The applicable rules of exponents are ...

(ab)^c = (a^c)(b^c)

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

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3 years ago

What is 80% of 80 round to the nearest hundreds

8090 [49]

512,000 80 times 100 times 80 times .8

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3 years ago

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