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tia_tia [17]
4 years ago
5

It is believed that 43% of the US population can play the piano, 28% can play the guitar, 15% can play the harmonica, 12% can pl

ay the drums, and 2% can play other instruments. You want to take a simple random sample of individuals to test this claim. What is the smallest number of people required for the sample to meet the conditions for performing inference?
250
150
100
43
2
Advanced Placement (AP)
1 answer:
Bess [88]4 years ago
5 0

Answer: 100

Explanation:

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Because sound moves faster in warm air than colder air, the wave bends away from the warm air and back towards the the ground.

7 0
3 years ago
11 You are not allowed to park within<br> feet of a railroad crossing.
ser-zykov [4K]

Answer:

You are not allowed to park within 50  feet of a railroad crossing.

Explanation:

8 0
3 years ago
Please help me solve this problem.
tresset_1 [31]
Do you have to make a table?
3 0
3 years ago
When an experiment is conducted, one and only one of three mutually exclusive events S1, S2, and S3 can occur, with
Arturiano [62]

Answer:

P(S_3|A) = \frac{2}{9}

Explanation:

Given

P(S1) = 0.3           P(S_2) = 0.5      P(S_3) = 0.2

P(A|S_1) = 0.3       P(A|S_2) = 0.1     P(A|S_3) = 0.2

Required

Determine P(S_3|A)

Using Bayes' theorem:

P(S_3|A) = \frac{P(S_3) * P(A|S_3)}{P(S_1) * P(A|S_1) + P(S_2) * P(A|S_2) + P(S_3) * P(A|S_3)}

So, we have:

P(S_3|A) = \frac{0.2 * 0.2}{0.3 * 0.3+ 0.5* 0.1 + 0.2 * 0.2}

P(S_3|A) = \frac{0.04}{0.18}

Multiply by 100/100

P(S_3|A) = \frac{4}{18}

P(S_3|A) = \frac{2}{9}

8 0
3 years ago
**80 Points** Please Answer!
dolphi86 [110]
So let's make p = dominant allele and q = recessive allele
p+q = 1, and (p+q)^2 = 1^2 thus
p^2 + 2pq + q^2 = 1, where p^2 = homozygous dominant, 2pq = heterozygous, and q^2 = homozygous recessive
So if p = .84, then q = 1-.84 = .16

a) recessive phenotype = q^2 = (.16)^2 = .0256
= 2.6%

b) dominant allele = p = .84 = 84%

c) heterozygous genotype = 2pq = 2(.84)(.16)
= .269 = 26.9%

4 0
4 years ago
Read 2 more answers
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