All categories

2 years ago

Find the slope of a line traveling through the points (8, -3) and (2, 6)(8,−3)and(2,6).

Mathematics

1 answer:

Sauron [17]2 years ago

6 0

Answer:

not sure if this is what youre looking for but here

y=-3/2x+9

Step-by-step explanation:

You might be interested in

(?,3) is on the line y=2x+5 what is the other coordinate

Dmitriy789 [7]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Substitute it into the equation:

3 = 2x + 5

Subtract 5 from both sides:

-2 = 2x

Divide both sides by 2:

x = -1

The other coordinate is -1

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago

Read 2 more answers

Help? pls?? I've got the first part, just need a lil help

OlgaM077 [116]

Find the time it will take:

195 miles / 50 miles per hour = 3.9 hours.

1 hour = 60 minutes:

0.9 hours x 60 = 54 minutes.

3.9 hours = 3 hours and 54 minutes.

Add 3 hours and 54 minutes to the time it leaves:

3:30 pm + 3 hours = 6:30 PM

6:30 + 54 minutes = 7:24 PM

8 0

2 years ago

An arithmetic sequence begins as follows: a1=13 a2=19 Which of the following gives the definition of its nth term?

Otrada [13]

Answer:

the nth term of the sequence is $a_n=6n+7$

Step-by-step explanation:

Given : An arithmetic sequence begins as follows: $a_1=13, a_2=19$

To find : Which of the following gives the definition of its nth term?

Solution :

The nth term of the A.P is $a_n=a+(n-1)d$

The first term is $a=a_1=13$

The common difference is $d=a_2-a_1$

$d=19-13=6$

Substitute in the formula,

$a_n=13+(n-1)6$

$a_n=13+6n-6$

$a_n=6n+7$

Therefore, the nth term of the sequence is $a_n=6n+7$

5 0

3 years ago

X=5y<br> 3x=7y+16 <br><br> substitution method, algebra 1

Korolek [52]

<span>3x=7y+16
15y=7y + 16
15y - 7y = 16
8y = 16
y = 8/16
y = 2
hope this helps you !!! =')</span>

7 0

3 years ago

What is 2 to the power of 4 over 3 equal to? (5 points)

ryzh [129]

Answer:

The answer is the option C

cube root of $16$

Step-by-step explanation:

Remember that

$a^{\frac{x}{y}} =\sqrt[y]{a^{x}}$

in this problem we have

$a^{\frac{x}{y}}=2^{\frac{4}{3}}$

therefore

$2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}$

4 0

3 years ago