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bagirrra123 [75]
3 years ago
8

What is .2 repeating, 1/5, .02 from least to greatest

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

.02, 1/5, .2 repeating

Step-by-step explanation:

.02

1/5 = 0.2                (Simply divide 1 by 5)

.2 repeating




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Complete Question:

Triangle abc has the angle mesausres shown.

m<A = (2x)°

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Which statement is true about the angles?

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C. m<A and m<B are complementary

D. m<A + m<C = 120°

Answer:

A. m<A = 20°

Step-by-step explanation:

m<A + m<B + m<C = 180° (sum of interior angles of a triangle)

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A. m<A = 20°

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Step-by-step explanation:

so, we have a large triangle made of the 2 cables as legs and the ground distance AB as baseline.

the tower is the height to the baseline of that large triangle.

let's call the top of the tower T.

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we know the angle A = 62°, and angle B = 72°.

assuming that AB is a truly horizontal line that means that the 2 legs (cables) have different lengths, the triangle is not isoceles, and the tower is not in the middle of the baseline.

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angle T = 180 - 90 - 62 = 28°

the other has the sides

BT, height (tower), q

angle B = 72°

angle T = 180 - 90 - 72 = 18°

now remember the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the sides and the associated angles being opposite.

p/sin(28) = height/sin(62)

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(12 - q)/sin(28) = height/sin(62)

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and therefore, as height = height we get

(12 - q)×sin(62)/sin(28) = q×sin(72)/sin(18)

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12×sin(62)×sin(18) - q×sin(62)×sin(18) =

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12×sin(62)×sin(18) = q×sin(72)×sin(28) + q×sin(62)×sin(18) =

= q×(sin(72)×sin(28) + sin(62)×sin(18))

q = 12×sin(62)×sin(18) / (sin(72)×sin(28) + sin(62)×sin(18))

q = 4.551603755... m

p = 12 - q = 7.448396245... m

height = q×sin(72)/sin(18) = 14.00839594... m ≈ 14 m

the cell tower is about 14 m tall.

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