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Westkost [7]
3 years ago
8

Fill in the boxes to show two ways you can find 8+6​

Computers and Technology
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

8+6

6+8

Explanation:

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Here is a nested loop example that graphically depicts an integer's magnitude by using asterisks, creating what is commonly call
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Answer:

Please find the code in the attached file.

Output:

Please find the attached file.

Explanation:

In this code a "num" variable is declared that use while loop that check num value greater than equal to 0.

Inside the loop we input the "num" value from the user-end and use if the value is positive it will define a for loop that calculates the quotient value as integer part, and use the asterisks to print the value.

If input value is negative it print a message that is "Goodbye".

Please find the code link:   https://onlinegdb.com/7MN5dYPch2

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David is taking a test. To answer a question, he first covers up the answer choices. Next, he tries to answer the question. Then
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Answer:

Multiple choice

Explanation:

I got 100 on the assignment

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Misspelet errors are displays with a ...<br>.. below them<br>​
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Answer:

The are displayed with red lines below them

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Take the average of some numbers. Show all the numbers that are below average. You can assume that there will not be more than 2
olchik [2.2K]

Here is code in java.

import java.util.*; // import package

class Main //  creating class

{

public static void main (String[] args) // main method

{

Scanner br=new Scanner(System.in); // scanner class for input

       int []a=new int[20]; // declaring array

       int count=0,x,j; // creating variable

       int sum =0;

       System.out.println("Enter a weight (0 to stop):");

       x=br.nextInt(); // taking input

while(x!=0) // iterating over the loop

       {

           a[count] = x;

           count++;

           System.out.println("Enter a weight (0 to stop):");

           x=br.nextInt();

}

       for( j=0;j<count;j++) // iterating over the loop

       {

       sum+=a[j];

       }

       double avg = sum/(double)count;

       System.out.println("The total is: "+sum);

       System.out.println("The average is: "+avg);

       System.out.println("Here are all the numbers less than the average: ");

     for( j=0;j<count;j++) //  // iterating over the loop

       {

           if(a[j]<avg)

           System.out.print(a[j]+" ");

       }

}

}

Explanation:

First create an object of "Scanner" class to read input from the user.

Create an array of size 20, which store the number given by user.Ask user

to give input and keep the count of number in the variable "count". If user

give input 0 then it will stop taking input.And then calculate sum of all the

input.It will calculate average by dividing the sum with count and print it.

It will compare the all elements of array with average value, if the element

is less than average, it will print that element.

Output:

Enter a weight (0 to stop):

1

Enter a weight (0 to stop):

2

Enter a weight (0 to stop):

3

Enter a weight (0 to stop):

4

Enter a weight (0 to stop):

5

Enter a weight (0 to stop):

6

Enter a weight (0 to stop):

7

Enter a weight (0 to stop):

8

Enter a weight (0 to stop):

9

Enter a weight (0 to stop):

10

Enter a weight (0 to stop):

0

The total is: 55

The average is: 5.5

Here are all the numbers less than the average:

1 2 3 4 5

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3 years ago
How do you write a multiplication formula in excel with an absolute refrence?
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To multiply all the numbers in column A by cell C2, add $ symbols to the cell reference like this: $C$2, which you can see in the example below. Using $ symbols tells Excel that the reference to C2 is “absolute,” so when you copy the formula to another cell, the reference will always be to cell C2.
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