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Artemon [7]
3 years ago
11

The partners of a small architectural firm are constantly busy with evolving client requirements. To meet the needs of their cli

ents, the architects must visit several job sites per day. To share and send sensitive project/client information back to the office or with clients, the employees dial into the IPSec-based VPN remotely. For classified proprietary information, two separate extranets were set up with partners in the engineering firm on a server housed inside the office.
What firewall setup would provide the firm both flexibility and security? Justify your response.
Computers and Technology
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

Check the explanation

Explanation:

IPSec-based VPN is configured in two different modes namely

IPSec Tunnel mode and IPSec Transport mode so here we are using IPsec transport mode which is used for end to end communications between a client and a server in this original IP header is remain intact except the IP protocol field is changed and the original protocol field value is saved in the IPSec trailer to be restored when the packet is decrypted on the other side due to this arrangement you need to use application based firewall because there are certain specific rules that can address the particular field (explained above-change in IP protocol field) which at the other end need to be same so at the type of decryption, original IP protocol field can be matched.

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Convert 105 decimal to 128 binary form
krok68 [10]

Answer:

1101001 is binary 105

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6 0
2 years ago
Write the constructor for the Theater class. The constructor takes three int parameters, representing the number of seats per ro
sp2606 [1]

Answer:

See explaination

Explanation:

class Seat {

private boolean available;

private int tier;

public Seat(boolean isAvail, int tierNum)

{ available = isAvail;

tier = tierNum; }

public boolean isAvailable() { return available; }

public int getTier() { return tier; }

public void setAvailability(boolean isAvail) { available = isAvail; } }

//The Theater class represents a theater of seats. The number of seats per row and the number of tier 1 and tier 2 rows are

//determined by the parameters of the Theater constructor.

//Row 0 of the theaterSeats array represents the row closest to the stage.

public class Theater {

private Seat[][] theaterSeats; /** Constructs a Theater object, as described in part (a). * Precondition: seatsPerRow > 0; tier1Rows > 0; tier2Rows >= 0 */

public Theater(int seatsPerRow, int tier1Rows, int tier2Rows) {

theaterSeats= new Seat[tier1Rows+tier2Rows][seatsPerRow];

}

public boolean reassignSeat(int fromRow, int fromCol, int toRow, int toCol) {

if(theaterSeats[toRow][toCol].isAvailable()) {

int tierDestination =theaterSeats[toRow][toCol].getTier();

int tierSource =theaterSeats[fromRow][fromCol].getTier();

if(tierDestination<=tierSource) {

if(tierDestination==tierSource) {

if(fromRow<toRow) {

return false;

}else {

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}

}

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}else {

return false;

}

}else {

return false;

}

}

public static void main(String[] args) {

//Lets understand it with simple example

Theater t1 = new Theater(3,1,2);

//Our threater has 3 seat in each row and we have one tier 1 row and 1 tier 2 row

//total no of seat will be 9.

//Lets create our seat

t1.theaterSeats[0][0] = new Seat(true,1);

t1.theaterSeats[0][1] = new Seat(false,1);

t1.theaterSeats[0][2] = new Seat(true,1);

t1.theaterSeats[1][0] = new Seat(true,2);

t1.theaterSeats[1][1] = new Seat(true,2);

t1.theaterSeats[1][2] = new Seat(true,2);

t1.theaterSeats[2][0] = new Seat(false,2);

t1.theaterSeats[2][1] = new Seat(false,2);

t1.theaterSeats[2][2] = new Seat(true,2);

//Lets print out theater and see which seat is available or which is not

System.out.println("Theater===>");

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

System.out.println("(2,1) want to change seat to (0,0)");

System.out.println("["+2+"]"+"["+1+"]"+"===>"+"["+0+"]"+"["+0+"]");

t1.reassignSeat(2, 1, 0, 0);

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

}

}

5 0
4 years ago
Task manager is showing an application as “not responding.” what can you do?
34kurt
I think it's b because "end application" would make the most sence
8 0
4 years ago
(70 points) This is a legit question that I have for a device FOR my homework.
guapka [62]

Answer:

it might be locked down so hold down the button for 20 sec and do a hard shut down, if it doesn't cut on try holding it down for down for 30 secs.  . IF that doesn't work there should be a port next to the power button. you can connect a micro-b cable to the kindle and then connect it to a computer or laptop if you have one.  There is a video where it shows you how to take it apart and repair if none of this helps

Explanation:  i hope this helps

7 0
4 years ago
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Answer:

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Explanation:

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3 years ago
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