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3 years ago

8

Max builds rail fences.for one style of fence,each section uses 3 vertical fence post and 6 horizontal rails.how many rails does

he need for a fence taht has 33 post. i need all the answers i can get

1 answer:

Goryan [66]3 years ago

6 0

He will need 66 :) the answer is 66

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Alex has a rectangle piece of red paper that is 4 centimeter wide .its length is twice it's width she glues a piece of paper blu

xenn [34]

4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.

8 0

3 years ago

As an estimation we are told 5 miles is 8 km.

melamori03 [73]

Answer:

Step-by-step explanation:

52.5 mi(8 km/5mi) = 84 km

3 0

3 years ago

Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of

kotykmax [81]

Given:
Inner cone: diameter = 12 cm ; height = 6 cm
Outer layer: diameter = 12 cm ; height = 15 cm

Volume of a cone = π r² h/3

Inner cone: V = 3.14 * (6cm)² * 6cm/3 = 3.14 * 36cm² * 2cm = 226.08 cm³
Outer layer: V = 3.14 * (6cm)² * 15cm/3 = 3.14 * 36cm² * 5cm = 565.20 cm³

Volume of Outer layer : 565.20 cm³
less: Volume of inner layer:<u> 226.08 cm³</u>
Volume of cream filling: 339.12 cm³

5 0

3 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

victus00 [196]

Answer:

a) $\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)$ , b) $\frac{dB}{dt}\approx 5.595$

Step-by-step explanation:

a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:

$\frac{dB}{dt} = \left(\frac{2\pi}{4.2} \right)\cdot 0.25\cdot \cos (2\pi\cdot \frac{t}{4.2})$

$\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)$

b) The rate of increase after one day is:

$\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \left(2\pi \cdot \frac{1}{4.2} \right)$

$\frac{dB}{dt}\approx 5.595$

4 0

3 years ago

"what quadrant is...." PLEASE PLEASE HELP!!!! Thank you so so much!!! *will give brainliest*

sdas [7]

Given:

$\tan \theta > 0$ and $\sec \theta$ .

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only $\sin \theta, \text{cosec}\theta$ are positive and others are negative.

In III quadrant, only $\cot \theta, \tan\theta$ are positive and others are negative.

In IV quadrant, only $\cos \theta, \sec\theta$ are positive and others are negative.

We have,

$\tan \theta > 0$ and $\sec \theta$ .

Here, $\tan \theta$ is positive and $\sec \theta$ is negative. So, $\theta$ lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

4 0

3 years ago