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inna [77]
3 years ago
8

Max builds rail fences.for one style of fence,each section uses 3 vertical fence post and 6 horizontal rails.how many rails does

he need for a fence taht has 33 post. i need all the answers i can get

Mathematics
1 answer:
Goryan [66]3 years ago
6 0
He will need 66 :) the answer is 66
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Alex has a rectangle piece of red paper that is 4 centimeter wide .its length is twice it's width she glues a piece of paper blu
xenn [34]
4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.
8 0
3 years ago
As an estimation we are told 5 miles is 8 km.
melamori03 [73]

Answer:

Step-by-step explanation:

52.5 mi(8 km/5mi) = 84 km

3 0
3 years ago
Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of
kotykmax [81]
Given:
Inner cone: diameter = 12 cm ; height = 6 cm
Outer layer: diameter = 12 cm ; height = 15 cm

Volume of a cone = π r² h/3

Inner cone: V = 3.14 * (6cm)² * 6cm/3 = 3.14 * 36cm² * 2cm = 226.08 cm³
Outer layer: V = 3.14 * (6cm)² * 15cm/3 = 3.14 * 36cm² * 5cm = 565.20 cm³

Volume of Outer layer :         565.20 cm³
less: Volume of inner layer:<u> 226.08 cm³</u>
Volume of cream filling:        339.12 cm³
5 0
3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
victus00 [196]

Answer:

a) \frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right), b) \frac{dB}{dt}\approx 5.595

Step-by-step explanation:

a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:

\frac{dB}{dt} = \left(\frac{2\pi}{4.2} \right)\cdot 0.25\cdot \cos (2\pi\cdot \frac{t}{4.2})

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)

b) The rate of increase after one day is:

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \left(2\pi \cdot \frac{1}{4.2} \right)

\frac{dB}{dt}\approx 5.595

4 0
3 years ago
"what quadrant is...." PLEASE PLEASE HELP!!!! Thank you so so much!!! *will give brainliest*
sdas [7]

Given:

\tan \theta > 0 and \sec \theta.

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only \sin \theta, \text{cosec}\theta are positive and others are negative.

In III quadrant, only \cot \theta, \tan\theta are positive and others are negative.

In IV quadrant, only \cos \theta, \sec\theta are positive and others are negative.

We have,

\tan \theta > 0 and \sec \theta.

Here, \tan \theta is positive and \sec \theta is negative. So, \theta lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

4 0
2 years ago
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