4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.
Answer:
Step-by-step explanation:
52.5 mi(8 km/5mi) = 84 km
Given:
Inner cone: diameter = 12 cm ; height = 6 cm
Outer layer: diameter = 12 cm ; height = 15 cm
Volume of a cone = π r² h/3
Inner cone: V = 3.14 * (6cm)² * 6cm/3 = 3.14 * 36cm² * 2cm = 226.08 cm³
Outer layer: V = 3.14 * (6cm)² * 15cm/3 = 3.14 * 36cm² * 5cm = 565.20 cm³
Volume of Outer layer : 565.20 cm³
less: Volume of inner layer:<u> 226.08 cm³</u>
Volume of cream filling: 339.12 cm³
Answer:
a)
, b) 
Step-by-step explanation:
a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:


b) The rate of increase after one day is:


Given:
and
.
To find:
The quadrant.
Solution:
We know that,
In I quadrant, all trigonometric ratios are positive.
In II quadrant, only
are positive and others are negative.
In III quadrant, only
are positive and others are negative.
In IV quadrant, only
are positive and others are negative.
We have,
and
.
Here,
is positive and
is negative. So,
lies in the III quadrant.
Therefore, the correct option is C, i.e., III.