2t^2+5t+2 Does anyone know this?
1 answer:
2t^2 + 5t + 2
First, break the terms into groups:
(2t^2 + t)(5t + 2)
Then factor out x from the first group:
t(2t + 1)
Then factor out 2 from the second group:
2(2t + 1)
Combined, it should look like this:
t(2t + 1) + 2(2t + 1)
Finally, factor out the common term:
(2t + 1)(t + 2)
The factors of 2t^2+ 5t + 2 are: (2t + 1)(t + 2).
The graph of 2t^2+ 5t + 2 is attached as well.
Hope this explanation helps.
First, break the terms into groups:
(2t^2 + t)(5t + 2)
Then factor out x from the first group:
t(2t + 1)
Then factor out 2 from the second group:
2(2t + 1)
Combined, it should look like this:
t(2t + 1) + 2(2t + 1)
Finally, factor out the common term:
(2t + 1)(t + 2)
The factors of 2t^2+ 5t + 2 are: (2t + 1)(t + 2).
The graph of 2t^2+ 5t + 2 is attached as well.
Hope this explanation helps.
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Answer:
Step-by-step explanation:
Expression for the rectangular area and perimeter are, respectively:
After some algebraic manipulation, area expression can be reduce to an one-variable form:
The first derivative of the previous equation is:
Let the expression be equalized to zero:
The second derivative is:
According to the Second Derivative Test, the critical value found in previous steps is a maximum. Then:
The maximum area is: