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Licemer1 [7]
3 years ago
10

2t^2+5t+2 Does anyone know this?

Mathematics
1 answer:
nevsk [136]3 years ago
8 0
2t^2 + 5t + 2

First, break the terms into groups:

(2t^2 + t)(5t + 2)

Then factor out x from the first group:
t(2t + 1)

Then factor out 2 from the second group:
2(2t + 1)

Combined, it should look like this:
t(2t + 1) + 2(2t + 1)

Finally, factor out the common term:
(2t + 1)(t + 2)

The factors of 2t^2+ 5t + 2 are: (2t + 1)(t + 2).

The graph of 2t^2+ 5t + 2 is attached as well.

Hope this explanation helps.

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Step-2 : Find two factors of  -60  whose sum equals the coefficient of the middle term, which is   -11 .

     -60    +    1    =    -59

     -30    +    2    =    -28

     -20    +    3    =    -17

     -15    +    4    =    -11    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -15  and  4

                    6n2 - 15n + 4n - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3n • (2n-5)

             Add up the last 2 terms, pulling out common factors :

                   2 • (2n-5)

Step-5 : Add up the four terms of step 4 :

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Final result :

 (2n - 5) • (3n + 2)

4 0
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