2t^2+5t+2 Does anyone know this?
1 answer:
2t^2 + 5t + 2
First, break the terms into groups:
(2t^2 + t)(5t + 2)
Then factor out x from the first group:
t(2t + 1)
Then factor out 2 from the second group:
2(2t + 1)
Combined, it should look like this:
t(2t + 1) + 2(2t + 1)
Finally, factor out the common term:
(2t + 1)(t + 2)
The factors of 2t^2+ 5t + 2 are: (2t + 1)(t + 2).
The graph of 2t^2+ 5t + 2 is attached as well.
Hope this explanation helps.
First, break the terms into groups:
(2t^2 + t)(5t + 2)
Then factor out x from the first group:
t(2t + 1)
Then factor out 2 from the second group:
2(2t + 1)
Combined, it should look like this:
t(2t + 1) + 2(2t + 1)
Finally, factor out the common term:
(2t + 1)(t + 2)
The factors of 2t^2+ 5t + 2 are: (2t + 1)(t + 2).
The graph of 2t^2+ 5t + 2 is attached as well.
Hope this explanation helps.
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Answer:
C(t)=5000 -10t
Step-by-step explanation:
There are many examples in the real world of relationships that are functions.
For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.
If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:
Where:
C (t): Amount of water in the tank as a function of time
: Initial amount of water in the tank at time t = 0
a: amount of water lost per hour
t: time in hours
Then the equation is:
The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.
Its domain is the set of all positive real numbers t between [0,500]
Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty
Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres