Question

Brian is solving the equation x^2-3/4x=5. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Answer 1

The answer is A
Why?
x^2 -3/4 x =5
(x - 3/8)^2 = 5 + 9/64

Answer 2

Given equation is :

$x^{2} -\frac{3x}{4} =5$

Step 1: half of coefficient of x

$\frac{-3}{4} *\frac{1}{2} = \frac{-3}{8}$

Squaring this we get

$(\frac{-3}{8} )^{2} = \frac{9}{64}$

step 2:

Adding $\frac{9}{64}$ to both sides

$x^{2} -\frac{3x}{4} +\frac{9}{64} = 5 +\frac{9}{64}$