Since R is the midmoint of QS that means that QR and RS are equal to each other. So first you need to find x. There are many different ways to set up the equation to solve for x, but I'll show you the easiest one:
QR+QS=RT+QR
(2x-4)+(2x-4)=(8x-43)+(2x-4)
Combine like terms:
4x-8=10x-47
Isolate Variable:
4x-8=10x-47
-4x -4x
6x-47=-8
Isolate Constant:
6x-47=-8
+47 +47
6x=39
Divide:
x=6.5
Check Your Answer:
(Plug in 6.5 as x)
(4(6.5)-8)=(8(6.5)-43)+(2(6.5)-4)
18=18
Answer:
We need to solve this equation:
We pass -3 to the right summing:
We pass the 4x that is dividing to the right multiplying:
We pass the 20 of the right to the left dividing:
Now, we know , so we can verify:
TRUE
Parenthesis
Exponents
Multiplication
Division
Adding
Subtracting
Answer:
Step-by-step explanation:
Not exactly sure what your question is - I am assuming that it is something like:
Show/prove that for any integer x, x^2 - x is even.
Suppose that x is an even integer. The product of an even integer and any other integer is always even (x = 2n, so x * y = 2 n * y which is even. Therefore x^2 is even. An even minus an even is even. (The definition of an even number is that it is divisible by 2 or has a factor of 2. So the difference of even numbers could be written as 2*( the difference of the two numbers divided by 2); therefore the difference is even)
Suppose that x is an odd integer. The product of 2 odd numbers is odd - each odd number can be written as the sum of an even number and 1; multiplying the even parts with each other and 1 will produce even; multiplying the 1's will produce 1, so the product can be written as the sum of an even number and 1 - which is an odd number. The difference between two odd numbers is even - the difference between the even parts is even (argument above), the difference between 1 and 1 is zero, so the result of the difference is even.
x^2 is therefore even if x is even and odd if x is odd; The difference x^2 - x is even by the arguments above.
249926 should be right because it saids fewer that must mean you subtrac
