Question

The picture is sideways. Please help, much appreciated! BRAINLIEST WILL BE GIVEN FOR THE HELP (SHOW WORK).​

Answer 1

Answer:

• 14 m

Step-by-step explanation:

Let the shorter side be x

Then the longer side is x + 1

Perimeter is:

• P = 2( x + x + 1) = 2(2x + 1) = 4x + 2

The value of perimeter is at most 60 meters. P ≤ 60.

Solve the inequality:

• 4x + 2 ≤ 60
• 4x ≤ 58
• x ≤ 58/4
• x ≤ 14.5

Since x is the integer, its greatest value is 14 m

Answer 2

${ \large{ \red{➾ \: \: \underline {\bf{ \underline{Let \: \: the \: \: width \: \: of \: \: rectangle \: \: be \: \: y}}}}}}$

${ \large{ \blue{➾ \: \: \underline {\bf{ \underline{Then \: \: the \: \: length \: \: of \: \: rectangle \: \: be \: \: (y + 1)}}}}}}$

${ \large{ \green{✪ \: \: \boxed{ \boxed{ \rm{Perimeter \: \: of \: \: rectangle = 2 \times (length + breadth)}}}}}}$

${ \large{ \pink{⇛ \: \: \sf{Perimeter = 2 \times (y + y + 1)}}}}$

${ \large{ \orange{⇛ \: \: \sf{Perimeter = 4y + 2}}}}$

${ \large{ \purple{ ✒ \: \: \: \tt{Here \: \: given = \: Perimeter \: \: is \: \: at \: \: most \: \: 60 \: m}}}}$

${ \large{ \red{ ⇝ \: \bf{So \: \: perimeter \leqslant 60}}}}$

${ \large{ \green{ \underline{ \rm{Now \: \: we \: \: have \: \: to \: \: solve \: \: inequality}} \colon}}}$

${ \large{ \blue{➠ \: \: \bf{4y + 2 \leqslant 60}}}}$

${ \large{ \orange{➠ \: \: \bf{4y \leqslant 58}}}}$

${ \large{ \purple{➠ \: \: \bf{y \leqslant { \cancel\dfrac{58} {4 }^ { \: \: {14.5}} {}} }}}}$

${ { \blue{➠ \: \: \bf{y(Width \: \: of \: \: rectangle ) \: \: \leqslant 14.5 \: \: \: { \underline{ \underline{(But \: \: y \: \: is \: \: an \: \: integer)}}}}}}}$

${ \large{ \rm{ \green{ ∴ \: \: \: \: { \boxed{ \boxed{\bf{y \: (Width \: \: of \: \: rectangle ) \: \: greatest \: \: value \: = 14 \: \: m \: \: \:{ \underline{ \underline{}}}}}}} }}} \: \: { \large{ \green{ \rm{Ans.}}}}}$