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gtnhenbr [62]
3 years ago
5

The picture is sideways. Please help, much appreciated! BRAINLIEST WILL BE GIVEN FOR THE HELP (SHOW WORK).​

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

Answer:

  • 14 m

Step-by-step explanation:

Let the shorter side be x

Then the longer side is x + 1

<u>Perimeter is:</u>

  • P = 2( x + x + 1) = 2(2x + 1) = 4x + 2

The value of perimeter is at most 60 meters. P ≤ 60.

<u>Solve the inequality:</u>

  • 4x + 2 ≤ 60
  • 4x ≤ 58
  • x ≤ 58/4
  • x ≤ 14.5

Since x is the integer, its greatest value is 14 m

Alja [10]3 years ago
5 0

{ \large{ \red{➾ \:  \:  \underline {\bf{ \underline{Let \:  \: the \:  \: width \:  \: of \:  \: rectangle \:  \: be \:  \: y}}}}}}

{ \large{ \blue{➾ \:  \:  \underline {\bf{ \underline{Then \:  \: the \:  \: length \:  \: of \:  \: rectangle \:  \: be \:  \: (y + 1)}}}}}}

{ \large{ \green{✪ \:  \:  \boxed{ \boxed{ \rm{Perimeter \:  \: of \:  \: rectangle = 2 \times (length + breadth)}}}}}}

{ \large{ \pink{⇛ \:  \:  \sf{Perimeter = 2 \times (y + y + 1)}}}}

{ \large{ \orange{⇛ \:  \: \sf{Perimeter = 4y + 2}}}}

{ \large{ \purple{ ✒ \:  \:  \: \tt{Here \:  \: given  =  \: Perimeter \:  \: is \:  \: at \:  \: most \:  \: 60 \: m}}}}

{ \large{ \red{  ⇝ \: \bf{So \:  \: perimeter  \leqslant 60}}}}

{ \large{ \green{ \underline{ \rm{Now \:  \: we \:  \: have \:  \: to \:  \: solve \:  \: inequality}} \colon}}}

{ \large{ \blue{➠ \:  \:  \bf{4y + 2  \leqslant  60}}}}

{ \large{ \orange{➠ \:  \:  \bf{4y  \leqslant  58}}}}

{ \large{  \purple{➠ \:  \:  \bf{y  \leqslant   { \cancel\dfrac{58} {4 }^ { \:  \: {14.5}} {}} }}}}

{ { \blue{➠ \:  \:  \bf{y(Width \:  \: of \:  \:  rectangle ) \:  \: \leqslant  14.5 \:  \:  \: { \underline{ \underline{(But \:  \: y \:  \: is \:  \: an \:  \: integer)}}}}}}}

{ \large{  \rm{ \green{ ∴ \:  \: \:  \: { \boxed{ \boxed{\bf{y \: (Width \:  \: of \:  \:  rectangle ) \:  \: greatest \:  \: value \:    =   14 \:  \: m \:  \:  \:{ \underline{ \underline{}}}}}}} }}} \:  \: { \large{ \green{ \rm{Ans.}}}}}

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