2*10^-3 + 3*10^-3
(2+3)*10^-3
5*10^-3
since the sum of coefficients of the 10^-3 are less than 10, we still have the same number of zeros
0.005
Answer:
D. 119
Step-by-step explanation:
To find the common difference, we take the second term and subtract the first term
2-(-7) = 9
We check by taking the third term and subtracting the second
11-2 = 9
The common difference is 9
The formula for an arithmetic sequence is
an = a1 +d(n-1)
where a1 is the first term, d is the common difference and n is the number of the term in the sequence
a1=-7, d=9 and we are looking for the 15th term so n=15
a15 = -7 +9(15-1)
a15 = -7+9(14)
=-7 +126
= 119
Answer:
Answer 5 1/4
Step-by-step explanation:
