Answer:
So since we have 2^-2 We can do 1/2^2 = 0.25
So if you have y^-x = 1/y^x
Well what's in the deck for example 3 red cards 2 yellow cards and a green card
First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate
x-y=40
<u>x+y=66 +</u>
2x+0y=106
2x=106
divide by 2
x=53
sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13
the numbers are 53 and 13
Answer:
24 cm²
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm)(2 cm) = 24 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
Answer:
<h3>
</h3>
Option B is the correct option.
Step-by-step explanation:
Apply cross product property
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Distribute 5 through the parentheses
⇒
Multiply the numbers
⇒
Move 5 to right hand side and change it's sign
⇒
Add the numbers
⇒
Divide both sides of the equation by 5
⇒
⇒
Hope I helped!
Best regards!!
