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Tamiku [17]
3 years ago
6

What is the constant rate of change between the two quantities

Mathematics
1 answer:
makkiz [27]3 years ago
5 0

Answer: number of pages is going by 10. The number of minutes is multiplying 2 times.

Step-by-step explanation:

To find the COP use an in book resource or search it pretty simple

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What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3
Rufina [12.5K]

Answer:

\frac{\Delta y}{\Delta x}  =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1}  =\frac{f(x_2)-f(x_1)}{x_2-x_1}

So, the average rate of change of:

f(x)=-x^2+3x+6

Over the interval -3

Is:

f(x_2)=f(3)=-(3)^2+3(3)+6=-9+9+6=6\\\\f(x_1)=f(-3)=-(-3)^2+3(-3)+6=-9-9+6=-12

\frac{\Delta y}{\Delta x}  =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3

Therefore, the average rate of change of this function over that interval is 3.

3 0
3 years ago
PLEASE ANSWER Chelsea is budgeting for her trip to the mall. She does not want to spend any more than $140. If she wants to buy
Tcecarenko [31]
Let s equal the number of shirts she can buy

140 > $28.50 + $20.75s
111.50 > 20.75s
5.37 > s

so we round down.  she can buy 5 shirts, plus the one dress and she would spend less than $140

4 0
3 years ago
Solve d = rt for r when d = 268mi and t=4hr
vichka [17]

Answer:

55 mph

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
What is the nearest tenth of 4.12311
svp [43]
Answer:

The nearest tenth of 4.12311 is 4.1
3 0
3 years ago
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What type of circuit measurement is made by placing a meter’s test leads in parallel with a deenergized component?
sladkih [1.3K]
The answer is that you are measuring "resistance".

If the segment is DE-energized, which means the entire device is shut down, at that point the main thing you can quantify with the meter- probes on the two ends of the segment is its resistance. The ordinary meter measures volts, amps, and ohms. If you touch 
the probes to the two ends of the part and the circuit is empowered, at that point you measure the voltage over the component.  If the circuit is DE-energized, at that point you are  measuring the component's resistance.
3 0
3 years ago
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