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miskamm [114]
1 year ago
7

How is solving for a variable similar to solving an equation? How is it different

Mathematics
1 answer:
storchak [24]1 year ago
6 0

When we say "solve for the variable", we mean to solve the equation because the solution of the equation is finding the unknown variable.

So, the similarity between "solving for a "variable" to "solving an equation" is that both actions imply looking at the value of that variable.

<h2>Similarity: both actions imply looking at the value of that variable.</h2>

On the other hand, a slight difference would be in the case of having several variables in the equation. In this case, both actions could represent slight differences, because if we have three different variables and we say "solve for <em>y</em>", that means we must isolate that variable, and the result is just an expression. But, if we say "solve the equation"

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3x+5=12-7x solve? Help ​
horsena [70]

Answer:

3x + 5 = 12 - 7x

⇒ 3x = 12 - 5 - 7x

⇒ 3x = 7 - 7x

⇒ 3x + 7x = 7

⇒ 10x = 7

⇒ x= 7 ÷ 10

⇒<u> x = 0.7</u>

8 0
2 years ago
The graph is of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
Reika [66]

The real solutions of f(x) = 0 is; x = -8, 0 and 4

<h3>How to find the roots of a polynomial graph?</h3>

When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.

Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.

From the given graph, the real solutions are at x = -8, 0 and 4

Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4

Read more about Polynomial roots graph at; brainly.com/question/14625910

#SPJ1

8 0
1 year ago
Please help with theses ? I’m kinda stuck on Algebra ll B. Anybody good on Algebra ?
pentagon [3]

Answer:

answer is b juicy how to do it

8 0
3 years ago
Which of the following expressions has the greatest value?
Vilka [71]

Answer:

2^5

Step-by-step explanation:

1^10 = 1 (1*1*1*1*1....)

5^2 = 25 (5*5)

2^5 = 32 (2*2*2*2*2)

3^3 = 27 (3*3*3)

5 0
3 years ago
a person leaves their house to go to the store. it takes 15 minutes at 12 mph to get to the store. They return home at 31 mph. W
trasher [3.6K]
\bf \cfrac{\stackrel{speed~forth}{12}+\stackrel{speed~back}{31}}{\stackrel{interval~forth}{1}+\stackrel{interval~back}{1}}\implies \cfrac{43}{2}\implies 21.5mph\textit{ on average}
5 0
3 years ago
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