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Shalnov [3]
3 years ago
9

Subtract: (-5x + 8) - (3x + 5)​

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

Solution: -8x + 3

Step-by-step explanation:

KHAN ACADEMY

(p.s. can u give me brainliest?)

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Step-by-step explanation:

I think you will get x this way:

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x=40°

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When you graph the three lines, the first two overlap. The third is parallel to those two.

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Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the trian
mart [117]

Answer:

The area is 11317.51

Step-by-step explanation:

The sum of 2 sides must be less than the third side (largest side) for a triangle to be formed.

b+c<a

133+174 < 240

A triangle can be formed

To use Herons formula for the area

We find S = 1/2( a+b+c)

                 = 1/2(240+133+174)

                 =  1/2 (547)

                     = 273.5


Area = sqrt( S (S-a) (S-b)(S-c))

           sqrt((273.5 ) (273.5 -240) (273.5-133) (273.5-174))

           sqrt((273.5)(33.5) (140.5) (99.5))

            sqrt(128085964.4)

           11317.50699

The area is 11317.51

5 0
3 years ago
Solve the inequality and express your answer in interval notation<br> x^2+8x+5 &lt;0
irakobra [83]

The interval notation is (-\sqrt{11}-4, \sqrt{11}-4)

Explanation:

The inequality is x^{2}+8 x+5

Let us complete the square, we get,

x^{2}+8 x+5+4^{2}-4^{2}

Simplifying, we have,

(x+4)^{2}+5-4^{2}

(x+4)^{2}-11

Adding both sides of the equation by 11, we get,

(x+4)^{2}

Since, we know that for u^{n} , if n is even then -\sqrt[n]{a}

Thus, writing the above expression in this form, we get,

-\sqrt{11}

Also, if a then a and u

Then ,we have,

-\sqrt{11} and x+4

Solving the inequalities, we get,

-\sqrt{11}\ \ \ \ \ \  and  x+4

Merging the intervals, we have,

-\sqrt{11}-4

Hence, writing the solution in interval notation, we have,

(-\sqrt{11}-4, \sqrt{11}-4)

Therefore, the answer is (-\sqrt{11}-4, \sqrt{11}-4)

7 0
3 years ago
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