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Mama L [17]
4 years ago
6

What shape has 4 sides that are different lengths

Mathematics
2 answers:
denis-greek [22]4 years ago
7 0
Theres no real name for a shape with uneven sides. I just realized that. A four sided figure is a quadrilateral. Or irregular polygon/quadrilateral. A four sided shape with no even sides.

Naya [18.7K]4 years ago
4 0
There is none it would be none

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Your test scores in reading class or 68, 85, 88, blank and 100%. What is the missing test score if you're mean average is an 84%
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Graph y=0.4x............................
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Isabelle has a five-sided chicken coop in her yard. Each side has an equal length,
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Answer:

3 yards.

Step-by-step explanation:

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The shape described above is a pentagon since it has 5 sides.

One side is 3/5 yards long.

Hence, the perimeter will be:

P = 3/5 + 3/5 + 3/5 + 3/5 + 3/5

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
LenaWriter [7]

Answer:

a) 0.0498

b) 0.1489

c) 0.1818

Step-by-step explanation:

Given:

Number of telephones = 6+6+6= 18

6 cellular, 6 cordless, and 6 corded.

a) Probability that all the cordless phones are among the first twelve to be serviced:

12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂

Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.

The possible ways of selecting thr remaining 6 telephones = ¹²C₆

Probability of servicing all cordless phones among the first twelve:

= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)

= \frac{1 * 924}{18564}

= 0.0498

b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:

Here,

One type must be serviced first

The 6 remaining to be serviced can be a combination of the remaining two types.

Since there a 3 ways to select one type to be serviced, the probability will be:

= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂

= \frac{3 * [(6)(6) + (15)(15) + (20)(20) + (15)(15) + (6)(6)]}{18564}

= \frac{2766}{18564}

= 0.1489

c) probability that two phones of each type are among the first six:

(⁶C₂)³/¹⁸C₆

\frac{3375}{18564}

=0.1818

5 0
4 years ago
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