What statement best describes the function?

Work out the area of ABCD.<br> Give your answer to 1 decimal place.

Mashutka [201]

Answer:

A is 90

C is 65

Step-by-step explanation:

6 0

2 years ago

I need to find the median ,mean,mode,range,and

Makovka662 [10]

Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3.
Mode: 99
The number that appears most often. In this case, 99 would be the mode.
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75

Hope this helped! :)

8 0

3 years ago

Read 2 more answers

Every five years in March, the Population of a certain town is recorded. In 1995, the town had a population of 4,500 people. Fro

alexgriva [62]

4,500 plus 15% is 5,175 minus 4% is 4,968 so your answer is 4,968.

5 0

3 years ago

How many years older will you be 1.60 billion seconds from now? (Assume a 365-day year.)

docker41 [41]

There are 31,536,000 Seconds in one year

In order to find out how much older you get, you just needed to divide it :

1,600,000,000 / 31,536,000

= 50,73 years older

hope this helps

3 0

2 years ago

g The downtime per day for a computing facility has mean 4 hours and standard deviation 0.9 hour. What assumptions must be true

Sedaia [141]

Answer:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

7 0

3 years ago