Answer:
Hello some parts of your question is missing below is the missing part
answer : A) p-value = 0.0019 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Step-by-step explanation:
A) using a 0.05 level of significance and test for independence of the quality of management
Test statistic :
∑ ( Oi - Ei )^2 / Ei
= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03
p-value = 0.0019
Df = 4 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Answer:
The compounded annually account will earn more interest over 10 years
Step-by-step explanation:
The rule of the simple interest is I = Prt, where
The rule of the compounded interest is A = P
, where
- n is the number of periods
The interest I = A - P
∵ Each account start with $200
∴ P = 200
∵ They have an interest rate of 5%
∴ r = 5% = 5 ÷ 100 = 0.05
∵ One account earns simple interest and the other is compounded
annually
∴ n = 1 ⇒ compounded annually
∵ The time is 10 years
∴ t = 10
→ Substitute these values in the two rules above
∵ I = 200(0.05)(10)
∴ I = 100
∴ The simple interest = $100
∵ I = A - P
∵ A = 200![(1+\frac{0.05}{1})^{1(10)}](https://tex.z-dn.net/?f=%281%2B%5Cfrac%7B0.05%7D%7B1%7D%29%5E%7B1%2810%29%7D)
∴ A = 325.7789254
∵ I = 325.7789254 - 200
∴ I = 125.7789254
∴ The compounded interest = $125.7789254
∵ The simple interest is $100
∵ The compounded interest is $125.7789254
∵ $125.7789254 > $100
∴ The compounded annually account will earn more interest
over 10 years
Answer:
lol
Step-by-step explanation:
nothiing
Answer:
2.93
Step-by-step explanation:
Answer:
5ab - 8a - 5b - 8
Step-by-step explanation:
each of these can be divided by 5