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soldi70 [24.7K]
3 years ago
10

Xp+yp= z Solve for p

Mathematics
1 answer:
juin [17]3 years ago
3 0
xp+yp=z\\\\p(x+y)=z \\\\\ \boxed{p=\frac{z}{x+y}}
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An advertising company charges $40 per half-page advertisement and $75 per full-page advertisement. Michael has a budget of $800
TEA [102]

Answer:

full page = 8

half page = 5

Step-by-step explanation:

two equations can be derived from the question

40x + 75y = 800 equation 1

x + y = 13 equation 2

x = number of half page advertisement

y = number of full page advertisement

multiply equation 2 by 40

40x + 40y = 520 equation 3

subtract equation 3 from 2

280 = 35y

y = 8

substitute for y in equation 2

x + 8 = 13

x = 13 - 8

x = 5

6 0
3 years ago
Thanks for the help in advance
grin007 [14]

Answer:

60

Step-by-step explanation:

6 0
2 years ago
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Please help I don’t understand
Kazeer [188]

Answer:

Me either

Step-by-step explanation:

3 0
3 years ago
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Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
HELP PLZ WILL GET BRAINLIEST
Nostrana [21]

for B I would get a large number of participants and see how much they walk in 1 day multiply it by 365 then by the average life span of human beings A might be similar. Hope that helped.

8 0
4 years ago
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