P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)
... = P(<100 | new)*P(new) + P(<100 | change)*P(change)
... = 0.90*0.70 + 0.20*0.30
... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms
Answer:
2x + 3y - 24 = 0
Step-by-step explanation:
2x + 3y = 18
3y = -2x + 18
y = 
x + 6
m = -2/3
y - 4 = -2/3(x - 6)
3y - 12 = -2x + 12
2x + 3y - 24 = 0
Answer:
The answer is 6
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Answer:
507,409
Step-by-step explanation:
if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.
30 ÷ 5 = 6
so we only have to quadruple the acorns 6 times.
if we start off with 124 acorns, this is what it will look like:
Day 0: 124 acorns
Day 5: 124 x 4 = 496 acorns
Day 10: 496 x 4 = 1984 acorns
Day 15: 1984 x 4 = 7936 acorns
etc... until day 30.
Day 30: 507904 acorns
I hope this was helpful :-)
