Answer
8
Step-by-step explanation:
algebra ll
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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The formula to find the area of a circle is pi x radius^2.
pi = 3.14 (in this case)
radius = 6
6^2 (6 x 6) = 36
36 x 3.14 (radius^2 x pi) = 113.04
So, the area of a circle with radius 6 cm is 113.04 cm.
The answer is rarefraction
Explanation
I got it right for my test in class
Answer:
(when x = 0)
Step-by-step explanation:
The initial value of the exponential equation is:
