Answer:
Four
Explanation:
Let the allele for black fur be B (the alternate will be b), the allele for active behavior be A (the alternate will be a), and the allele for light eyes be L (the alternate will be l).
<em>Heterozygous dominant for black fur = Bb</em>
<em>Heterozygous dominant for active behavior = Aa</em>
<em>Homozygous recessive for light eyes = ll</em>
Hence, the genotype for a male that is heterozygous for the dominant traits of black fur and active behavior but is homozygous recessive for light eyes will be BbAall.
Bb Aa ll
Possible Gametes
<em>BAl, Bal, bAl, and bal</em>
Therefore, the number of different types of gametes produced by the male mouse is four.
Answer:
They are small because they are growing on bare surfaces, not even soil, so they're just growing on abiotic things like rocks, so the first plants are more like weeds, lichens, small mosses, etc... because these are the only types of plants suited to turn this habitat back into its original climax community through means like nitrogen fixation. Also, because there's probably no to little nutrients there which can cause nutrients to be a limiting factor to their growth and cause them to be stunted. Need me to elaborate more?
Answer:
a) aaBb
b) Dimples and short eyelashes
c) 50%
d) 25%
Explanation:
Let the gene for dimples be A
Let the gene for eyelashes be B
a) Woman has no dimples (aa) and is heterozygous for long eyelashes (Bb) so her genotype : aaBb
b) Man is heterozygous for dimples (Aa) so he will have dimples and it is already given that he has short eyelashes (bb)
When aaBb X Aabb :
aB ab
Ab AaBb Aabb
ab aaBb aabb
c) Out of the four possible combinations, aaBb and aabb will be born without dimples so this couple has 50% chance to produce a child without dimples.
d) Only aabb will be born without dimples and without long eyelashes so the couple has 25% chance to produce a child without dimples and without long eyelashes.
Answer: D
Explanation: Cellulose is made up of simple sugars, the same way protein is made up of Amino acids
