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iris [78.8K]
3 years ago
8

Help? please lol school is so confuesing

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

\frac{6x}{x^{4} + 5}

Let's plug in 2 anywhere that we see an x:

\frac{6(2)}{(2)^{4} + 5}

\frac{12}{16 + 5}

\frac{12}{21}

Both the numerator and denominator are divisible by 3, so we can divide 3 out of each to get the final answer:

\frac{3 * 4}{3 * 7}

\frac{4}{7}

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Murrr4er [49]
21 is scale factor 6.
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Does anyone know this?? Pls help!
kozerog [31]

Answer: x^3 -12x^2+31x-96+ 292/x+3

The remainder is 292

Step-by-step explanation: I used synthetic division to get the answer and got the answer above. I hope this helped :)

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34 thousands + 36 hundreds + 18 tens + 2 ones is how many total
fredd [130]

Answer:

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Step-by-step explanation:

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3 years ago
Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
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3 years ago
How many edges does the following shape have?
SSSSS [86.1K]

Answer:

8

Step-by-step explanation:

Count each side and you get 8 sides.

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3 years ago
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