A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day (t in days). Find the insect population after 6 day
s, assuming that there are 50 insects at t = 0. (Round your answer to the nearest insect.)
1 answer:
Answer:
The insect population after 6 days is of 1639 insects.
Step-by-step explanation:
A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day
This means that 
The population of insects after x days is given by:

So



In which K is the initital population(which is 50). So

After 6 days:

Rounding to the nearest insect, 1639
The insect population after 6 days is of 1639 insects.
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Answer:
i think the answer might be b if not i'm sorry
Step-by-step explanation:
Answer:
Here,
length = 8m
height = 4m
4s = 15 per m^2
Now,
300 per meter = 300 * 15 per m^2
= 4500 per m^2
Answer:
8-42 = -34 will be applied
Answer:
A is 33.5430
B is 307,000
C is 285.39
D is 6,810
Not sure what the 33. is but that should be the right answer
6 divided by some number.