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3 years ago

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My doctor says that i should consume no more than 1200 calories a day. I have already consumed 750, and i am hoping to snack on

some snickers minis. If each mini is 75 calories, write and solve an inequality showing how many snickers minis i can eat!

1 answer:

Nataly [62]3 years ago

7 0

Answer:

1200 ≥ 750 + 75x

6 ≥ x

Step-by-step explanation

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Kyle is purchasing a refurbished phone. He is looking at the phone models 4, 5, and 6, with a protective case in red (R), blue (

konstantin123 [22]

Answer:

The choices Kyle has are option D.) {4R, 4B, 4C, 5R, 5B, 5C, 6R, 6B, 6C}

Step-by-step explanation:

The choices available to Kyle either of the models 4, or 5 or 6 and each model can have a protective case which can be either red(R) or blue(B) or camo(C).

So Kyle can have model 4 in red protective case, 4R, or model 4 in blue protective case(4B), or model 4 in camo protective case (4C) or

Kyle can have model 5 in red protective case, 5R, or model 5 in blue protective case(5B), or model 5 in camo protective case (5C) or

Kyle can have model 6 in red protective case, 6R, or model 6 in blue protective case(6B), or model 6 in camo protective case (6C).

So the choices Kyle has are option D.) {4R, 4B, 4C, 5R, 5B, 5C, 6R, 6B, 6C}

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3 years ago

Read 2 more answers

The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a

almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

$y=a(0.5)^{\frac{t}{72}}$

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

$y=a(0.5)^{\frac{1}{72} }$

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

= 0.0096a gms

Percentage decay every hour = $\frac{\text{Amount of decay}}{\text{Initial amount}}\times 100$

= $\frac{0.0096a}{a}\times 100$

= 0.958 %

≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

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aleksandr82 [10.1K]

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Answer:

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