The probability that the marbles selected are of the same colour is; 5/18
<h3>Probability of outcome</h3>
The probability that the marbles are the same colour includes:
- The probability of 2 reds, 2 whites, 2 greens.
The total number of marbles = 9 marbles.
Since, the selection is without replacement;
The probability of selecting same colour marbles is;
- {4/9×3/8} + {2/9×1/8} + {3/9×2/8}
The probability of selecting same colour marbles is therefore;
Read more on probability;
brainly.com/question/24756209
0%. You can't pick a 3 then pick a 3 again, as there is only one 3 available to be picked. 0/1
25% is equal to 100/25=1/4
We can substitute this into an equation to get the total number of wells where n can be equal to the total number of wells.
1/4*n=50
n/4=50
n=50*4
n=200
The total number of wells that were drilled was 200.
![\frac{\textbf{1}}{\textbf{20}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextbf%7B1%7D%7D%7B%5Ctextbf%7B20%7D%7D)
Step-by-step explanation:
Probability=![\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnumber%20of%20favourable%20outcomes%7D%7D%7B%5Ctext%7Btotal%20number%20of%20outcomes%7D%7D)
Probability for a randomly chosen girl to be senior=![\frac{\text{number of senior girls}}{\text{total number of girls}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnumber%20of%20senior%20girls%7D%7D%7B%5Ctext%7Btotal%20number%20of%20girls%7D%7D)
Probability for a randomly chosen girl to be senior=![\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B8%2B11%2B9%2B7%7D%3D%5Cfrac%7B7%7D%7B35%7D%3D%5Cfrac%7B1%7D%7B5%7D)
Probability for a randomly chosen boy to be senior=![\frac{\text{number of senior boys}}{\text{total number of boys}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnumber%20of%20senior%20boys%7D%7D%7B%5Ctext%7Btotal%20number%20of%20boys%7D%7D)
Probability for a randomly chosen girl to be senior=![\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%2B7%2B10%2B9%7D%3D%5Cfrac%7B9%7D%7B36%7D%3D%5Cfrac%7B1%7D%7B4%7D)
For two independent events,
Probability for both event 1 and event 2 to take place=![\text{probability of event 1} \times \text{probability of event 2}](https://tex.z-dn.net/?f=%5Ctext%7Bprobability%20of%20event%201%7D%20%5Ctimes%20%5Ctext%7Bprobability%20of%20event%202%7D)
Since choosing boys and girls is independent,
Probability for both boy an girl chosen to be senior=![\text{probability for boy to be senior}\times\text{probability for girl to be senior}](https://tex.z-dn.net/?f=%5Ctext%7Bprobability%20for%20boy%20to%20be%20senior%7D%5Ctimes%5Ctext%7Bprobability%20for%20girl%20to%20be%20senior%7D)
Probability for both boy and girl chosen to be senior=![\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B1%7D%7B20%7D)
So,required probability is ![\frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B20%7D)
SOLUTION;
![\sqrt[]{-36}\text{ = }\sqrt[]{(36)(-1)}\text{ = }\sqrt[]{36}\text{ x }\sqrt[]{-1\text{ }}\text{ = 6i}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B-36%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%2836%29%28-1%29%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B36%7D%5Ctext%7B%20x%20%7D%5Csqrt%5B%5D%7B-1%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%206i%7D)
Recall that the square root of the negative one is "i" meaning that it is a complex number and not a real number.