Answer:
2/13
Step-by-step explanation:
Since there's 4 of each card in the deck this means that there're 4 sixes and 4 aces, so 8 cards in a 52 card deck gives the problem 8/52 which equals 2/13
Answer:
;*((((((((((((((((((((((((((srry(((((((((((((((((()
Step-by-step explanation:
sjshchsjjxbsiskcjsidcnbvhdjdkcguziabcbhsjxjbdbxbxb vdjn bsj nnsjn nxnnxn b bxhzj baby b zn ncncjxj hb. b xjxjn bxnzjkxn
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
16 bc all sides of a square are congruent and area = LxW so 4x4=16
