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ivann1987 [24]
3 years ago
11

I need this fast guys. This is due tomorrow help a fellow comrade out

Mathematics
1 answer:
gavmur [86]3 years ago
3 0
So whats the answer. please help me I got a test of this
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Triangle ABC has the following coordinates: A(4 , 5), B(5 , 3), and C(2 , 3). Part A: If triangle ABC is dilated by a scale fact
Kobotan [32]

The new coordinates of A'B'C' creates a triangle that is larger than ABC.

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, reflection, rotation and dilation.</em>

If a point A(x, y) is dilated by a scale factor k, the new point is at A'(kx, ky).

Given that:

  • Triangle ABC has the following coordinates: A(4 , 5), B(5 , 3), and C(2 , 3)

If it is dilated by a scale factor of 3, the new point is at:

  • A'(12, 15), B'(15, 9) and C'(6, 9)

Therefore the new coordinates of A'B'C' creates a triangle that is larger than ABC.

Find out more on dilation at: brainly.com/question/10253650

8 0
3 years ago
The ratio of elena's height to pavai's height is 10:13. The ratio of elena's height to kamir's height is 2:3. Their total height
tensa zangetsu [6.8K]

Answer:

a) 10:13:3

b) 258 cm

Step-by-step explanation:

The ratio of elena's height to pavai's height is 10:13. The ratio of elena's height to kamir's height is 2:3. Their total height is 456 cm.

a) Find the ratio of elena's height to pavani's height to kamir's height in its simplest form.

10:13:3

b) What is pavani's height?

The ratio of elena's height to pavai's height is 10:13.

Their total height is 456 cm

Sum of proportions = 10 + 13 = 23

Hence:

13/23 × 456 cm

= 257.73913043 cm

Approximately = 258 cm

3 0
3 years ago
HELP ASAP!! WILL MARK BRAINIST!!! ASAP!!<br> n - 2 divided by -3 = -6 what is the value of n?
xenn [34]

Answer:

= -6 2/3

Step-by-step explanation:

3 0
3 years ago
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Calculus. Find the area.
matrenka [14]

Answer:

8/3 square units.

Step-by-step explanation:

First, visualize the area. You can refer to the attachment below.

To find the area then, we will integrate y from x = 0 to x = 2. Therefore:

\displaystyle A=\int_0^2x^2\, dx

Integrate:

\displaystyle A=\frac{1}{3}x^3\Big|_{0}^2

Evaluate:

\displaystyle A=\frac{1}{3}[2^3-0^3]=\frac{1}{3}(8)=\frac{8}{3}

The area is 8/3 square units.

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3 years ago
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Can x-2 ever be less than 0? Why or why not?
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Of course it can.  It always is if 'x' is less than 2.
5 0
3 years ago
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