9514 1404 393
Answer:
240°
Step-by-step explanation:
The sum of angles in a quadrilateral is 360°, so you have ...
a° +b° +60° +60° = 360°
a° +b° = 240° . . . . . . subtract 120° from both sides
D. √5 <span>
Let's first simplify the equation
sqrt(75)/sqrt(15)
Factor it
(sqrt(3)sqrt(5)sqrt(5)) / (sqrt(3)sqrt(5))
Now cancel the sqrt(3) and sqrt(5) on both top and bottom, giving
sqrt(5) / 1
sqrt(5)
So we're just left with the square root of 5. Checking the available options, you see that D. </span><span>√5 </span> is an exact match. So that's your answer.
The plane must be 3.38 miles away from the runway to begin the descent. The equation I used was "y = -0.1111111x + 0.3755682", 0.37~ being the height in feet (in miles) and -0.11~ being the descent. The x-intercept is located at 3.38.