Answer:
C. 210 miles.
Step-by-step explanation:
If Car 1 left 30 minutes earlier
than Car 2 therefore Car 2 traveled 3 hours
compared to Car 1's 3.5 hours
Car 1 traveled 3.5 x 42 mph = 147 miles
Car 2 travelled 3 x 50 mph = 150 miles
The distance between them would be
√147^2 + 150^2
= 210
Answer:
4.5 hours
Step-by-step explanation:
Assume the relation between points is a linear relation.
Use the given information as points in a linear equation.
Find the equation of the line; then find x when y = 25.75.
Find the equation of the line that passes through points (3, 23.5) and (8, 31).
y = mx + b
m = (y2 - y1)/(x2 - x1) = (31 - 23.5)/(8 - 3) = 7.5/5 = 1.5
y = 1.5x + b
Use point (8, 31) as x and y, and solve for b.
31 = 1.5(8) + b
31 = 12 + b
b = 19
The equation is
y = 1.5x + 19
Now let y = 25.75, and solve for x.
y = 1.5x + 19
25.75 = 1.5x + 19
6.75 = 1.5x
x = 4.5
Answer: 4.5 hours
maximum rms velocity formula
Answer:
c. first year: 240,000
second year: 150,000
Step-by-step explanation:
We let the number of cars made in the second year be X. Consequently, the number of cars made in the first year would be X+90000 since we are told that 90,000 more cars were made in the first year than in the second year. Furthermore, we are also told that the total number of cars constructed in these two years is 390,000, implying that;
X+X+90000=390000
2X+90000=390000
2X=390000-90000
2X=300000
X=150000; number of cars made in second year
The number made in the first year is thus;
150000+90000 = 240000