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3 years ago

NEED HELP ASAP!!!! How many square feet of outdoor carpet will we need for this whole?

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

Answer:

You will need 44 sq ft of carpeting

Step-by-step explanation:

First we can find the area of the larger rectangle and subtract the area of the smaller rectangle

Large rectangle:

equation for area: bh

= 12 * 4

=48 sq ft

Small rectangle:

equation: bh

= 2 * 2

=4 sq ft

48 - 4 = 44 sq ft

Marrrta [24]3 years ago

4 0

Answer:

44 square feet

Step-by-step explanation:

big one - small one

big one=12 x 4=48 square feet

small one=2 x 2=4 square feet

the total should be:

48 - 4=44 square feet

Hope it helps.

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

write each of the following word names as mixed if you purchase a hundred items that cost $0.25 each how much would the items co

docker41 [41]

Answer:$25 because if u times 100 and 0.25 u get 25

Step-by-step explanation:

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2 years ago

What is 59.69 written in standard form?

White raven [17]

It would be written as:

50+9+0.60+0.09

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2 years ago

write an equation in point-slope form of the line that passes through the point (-3,6) and has a slope of 5

RSB [31]

Answer:

y=5x + 21

Step-by-step explanation:

y=5x×b

6= -15+b

b=21

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3 years ago

What is mine times nine

statuscvo [17]

If you are meaning Nine times Nine the answer is 81.

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2 years ago