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allochka39001 [22]
3 years ago
15

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

, what is the value of b?
Mathematics
2 answers:
joja [24]3 years ago
7 0
Hello!

First of all we solve for the slope as seen below.

\frac{3+5}{-6+4} = -\frac{8}{2} = -4

Our slope is -4.

Now we substitute a point from our equation into slope intercept form, along with the slope. Then we solve for b. We will use (-4,-5)

-5=-4(-4)+b
-5=16+b
b=-21

Our final equation is shown below.

y=-4x-21

I hope this helps!
Gala2k [10]3 years ago
4 0

<u>Answer:</u>

-21

<u>Step-by-step explanation:</u>

Cause I just took the quiz.

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Deon rented a truck for one day there was a base fee of $19.99 and there was an additional charge of 98 cents for each mile driv
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Answer:

Deon drove the truck 201 miles.

Step-by-step explanation:

Base Fee + (.98* Number of miles)= Cost

19.99 + .98x = 216.97

Subtract 19.99 from both sides.

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Divide both sides by .98

x = 201

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3 years ago
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C would be the answer I think
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What attributes of a rectangles and rhombuses are also attributes of parallelogram
Scorpion4ik [409]

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3 years ago
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

g(-1) = -1

g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

4 0
3 years ago
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