Question

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

Answer 1

Hello!

First of all we solve for the slope as seen below.

$\frac{3+5}{-6+4} = -\frac{8}{2} = -4$

Our slope is -4.

Now we substitute a point from our equation into slope intercept form, along with the slope. Then we solve for b. We will use (-4,-5)

-5=-4(-4)+b
-5=16+b
b=-21

Our final equation is shown below.

y=-4x-21

I hope this helps!

Answer 2

Answer:

-21

Step-by-step explanation:

Cause I just took the quiz.