Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

Question

allochka39001 [22]

3 years ago

15

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

, what is the value of b?

Mathematics

2 answers:

joja [24] · Answer 1 · 2022-09-04T04:15:30+03:00

Hello!

First of all we solve for the slope as seen below.

$\frac{3+5}{-6+4} = -\frac{8}{2} = -4$

Our slope is -4.

Now we substitute a point from our equation into slope intercept form, along with the slope. Then we solve for b. We will use (-4,-5)

-5=-4(-4)+b
-5=16+b
b=-21

Our final equation is shown below.

y=-4x-21

I hope this helps!

Gala2k [10] · Answer 2 · 2022-09-04T05:20:39+03:00

Gala2k [10]3 years ago

4 0

<u>Answer:</u>

-21

<u>Step-by-step explanation:</u>

Cause I just took the quiz.