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fenix001 [56]
3 years ago
5

Evaluate the expression when a=−15 and b=−5. b2/a + 5

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

  • -2.5

Step-by-step explanation:

<u>Evaluate the expression:</u>

  • b²/(a + 5)

When a= −15 and b=−5

<u>Substitute values:</u>

  • b²/(a + 5) =
  • (-5)² / (-15 + 5) =
  • 25/(-10) =
  • -2.5

------------------------------------------------------------------

<u>In case the expression is b²/a + 5, the value is:</u>

  • b²/a + 5 =
  • (-5)²/(-15) + 5 =
  • 25/(-15) + 5 =
  • - 5/3 + 5 =
  • 10/3

-------------------------------------------------------------------

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Solve for x in the triangle. Round your answer to the nearest tenth.
hodyreva [135]

Answer:

x ≈ 11.7

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = \frac{adjacent}{hypotenuse} = \frac{x}{13} ( multiply both sides by 13 )

13 × cos26° = x , then

x ≈ 11.7 ( to the nearest tenth )

4 0
2 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 269 day
fenix001 [56]

Answer:

a) 279 b)254

Step-by-step explanation:

Mean = 269 days

standard deviation = 8 days

let n be the pregnancy lenght.  

using normal distribution formula

z = (n – mean)/ standard deviation

n = z * standard deviation + mean

Now, z values for the top 12% has to be found using a z table.

The top 12% means 88% of area under the curve. In this case z = 1,176

n = 1,176 * 8 + 269

n = 278.4 = 279

The bottom 3% means 97% of area under the curve. In this case z = -1,882

n = -1,882 * 8 + 269

n = 253.94 = 254

6 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
What is 15 greater than 3-4s
DochEvi [55]

Answer:

18-4s

Step-by-step explanation:

15+3-4s

You just simplify to get 18-4s.

Hope that helped!

5 0
3 years ago
Heeelp will give brainliest
ozzi

Answer:

42*7

Step-by-step explanation:

5 0
3 years ago
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