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3 years ago

Find the limit, if it exists. lim (x^3 -3x^2 +3)

Mathematics

1 answer:

Kruka [31]3 years ago

4 0

Answer:

-1

Step-by-step explanation:

Assuming problem is: x->2 (x^3 -3x^2 +3)

Since the expression is continuous at x=2,

then the limit can be found just by evaluating the expression at x=2.

2^3-3(2)^2+3

8-3(4)+3

8-12+3

-4+3

-1

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I need help with this<br> If x + 3 /3 = y + 2/ 2 ,then x/ 3 =

abruzzese [7]

Answer:

First solve for x

then substitute

Step-by-step explanation:

$\frac{x+3}{3}= \frac{y+2}{2}$

$6(\frac{x+3}{3}=\frac{y+2}{2})$

2x + 6 = 3y + 6

2x = 3y

$x = \frac{3y}{2}$

If $\frac{x+3}{3}= \frac{y+2}{2}$ then $\frac{x}{3}$ =

$x = \frac{3y}{2} /3 = \frac{y}3}$

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3 years ago

Create three geometric sequences of your own (including one that is decreasing). Extend your sequences to include five terms. Th

Karo-lina-s [1.5K]

Answer:

a) $a_n=5\,\,(2)^{n-1}$

b) $b_n=100\,\,(\frac{1}{2} )^{n-1}$

c) $c_n=160\,\,(-\frac{1}{2} )^{n-1}$

Step-by-step explanation:

a) Geometric sequence with first term 5 and common ratio 2, where the nth term can be calculated via:

$a_n=5\,\,(2)^{n-1}$

The first five terms are: $a_1=5;\,\,\,a_2=10;\,\,\,a_3=20; \,\,\,a_4=40;\,\,\,a_5=80$

b) Geometric sequence with first term 100 and common ratio 1/2, where the nth term can be calculated via:

$b_n=100\,\,(\frac{1}{2} )^{n-1}$

The first five terms are: $a_1=100;\,\,\,a_2=50;\,\,\,a_3=25; \,\,\,a_4=12.5;\,\,\,a_5=6.25$

c) Geometric sequence with first term 160 and common ratio -1/2, where the nth term can be calculated via:

$c_n=160\,\,(-\frac{1}{2} )^{n-1}$

The first five terms are: $a_1=160;\,\,\,a_2=-80;\,\,\,a_3=40; \,\,\,a_4=-20;\,\,\,a_5=10$

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3 years ago

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jonny [76]

Answer:

Step-by-step explanation:

I think your answer is y/8. It's a little unusually worded. If this is not correct, please leave a note.

The way I have answered it, I would word it as "What is the quotient of y divided by 8."

7 0

3 years ago

Which product is greater 9×15 or 9×17? Explain how you can trll without finding the products.

hram777 [196]

9x17 is greater. I’d say you can tell because 17 is greater than 15 so the product would be greater too

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