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a_sh-v [17]
3 years ago
12

What is 25% Of 30% Of 400?

Mathematics
1 answer:
marta [7]3 years ago
3 0

Answer:

25% of 30% of 400 = 30

33% decrease in value

Step-by-step explanation:

You can either get 30% of 400 first then 25% of 400 or you can get the total percentage of 400.

Method 1:

30% of 400 = 0.3 of 400 = 0.3 * 400 = 120

25% of 120 = .25 of 120 = .25 * 120 = 30

Method 2:

30% of 25% = 0.3 * 0.25 = 0.075 = 7.5% of 400

7.5% of 400 = 0.075 of 400 = 0.075 * 400 = 30

5.) To find the percentage  of the new price, you can build the equation below.

\frac{new price}{original price} = \frac{percent}{100}

\frac{200,000}{300,000}  = \frac{x}{100}

20,000,000 = 300,000x

x = 66.667

The percentage decrease in price is then 100% of the original price - 66.667% of the original price = 100% - 66.67% = 33.33% = 33% decrease.

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( For Brainly ) <br> On which body part a temporal lobe is placed?<br> The square root of 81 is?
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On which body part a temporal lobe is placed?

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You have a biased coin for which p(h)=pp(h)=p. you toss the coin 2020 times. what is the probability that you observe 88 heads a
Nat2105 [25]
The question describes a binomial probability with p(h) = p, then p(t) = 1 - p and number of trials (n) = 20

The probability of a binomial distribution is given by

P(x)=\, ^nC_xp^x(1-p)^{n-x}

Part A:

The probability of observing 8 heads and 12 tails is given by:

P(8)=\, ^{20}C_8p^8(1-p)^{20-8}=\, ^{20}C_8p^8(1-p)^{12}



Part B:

<span>You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.

Therefore, the probability of </span><span>observing more than 8 heads and more than 8 tails</span> is given by:

P(9)+P(10)+P(11) \\  \\ =\, ^{20}C_9p^9(1-p)^{20-9}+\, ^{20}C_{10}p^{10}(1-p)^{20-10}+\, ^{20}C_{11}p^{11}(1-p)^{20-11} \\  \\ =\, ^{20}C_9p^9(1-p)^{11}+\, ^{20}C_{10}p^{10}(1-p)^{10}+\, ^{20}C_{11}p^{11}(1-p)^{9}
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Solve for y<br> 4y + 8 = 29 - 5y
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Answer:

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4y+8=29-5y

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Next you are going to add 5y to each side of the equation.

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Read 2 more answers
A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
agasfer [191]

1. μ = 306,500

2.σ = 24,500

3. n = 150

4. μ_x = $306,500

5. σ_x = $2000

<h3>What is Standard deviation?</h3>

The standard deviation serves as a gauge for the degree of variation or dispersion among a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the mean of the collection.

With a standard deviation of $24,500 and an average mortgage debt of $306,500, Americans have a median mortgage debt.

<h3>According to the given information:</h3>

The population's average is

μ = 306,500

Standard deviation for the general population is

σ = 24500

Imagine 150 Americans are chosen at random for the sample.

n= 150

The sample mean is roughly normally distributed as a result of the high sample size, which is supported by the central limit theorem.

The population mean and sample mean would be the same,

μ_n = μ =306,500

Here is how to calculate the sample standard deviation:

\sigma_{x}=\frac{\sigma}{\sqrt{n}}

the sample size is n, and is the population standard deviation.

\begin{aligned}&\sigma_{x}=\frac{24,500}{\sqrt{150}} \\&\sigma_{x}=\$ 2,000\end{aligned}

The necessary conditions are thus:

1. μ = 306,500

2.σ = 24,500

3. n = 150

4. μ_x = $306,500

5. σ_x = $2000

To know more about Standard deviation visit:

brainly.com/question/16965372

#SPJ4

I understand that the question you are looking for is :

A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to compare the typical mortgage owed by their clients against other homebuyers. The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500. Suppose a random sample of 150 Americans is selected. Identify each of the following, rounding your answers to the nearest cent when appropriate:

1.1.  $mu=?\\2. $sigma=?\\3. $=n=$\\4. $mu_{overlinex}=$x=?\\5. $sigma_{overlinex}=$x=?

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