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kirza4 [7]
3 years ago
5

A scientist changes the temperature of a solution at a rate of

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

11 minutes

Step-by-step explanation:

I may be missing something. This is too simple.

88 degree change at 8 degrees per minute = 11 minutes.

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Identify the range of the function shown in the graph.
Masteriza [31]
The tan gray tan is black gray or green orange gray green and red violets are gray green and gray and tan and that would be your answer
6 0
2 years ago
For any integer x,x2-x will always produce an even value
Levart [38]

Consider expression x^2-x. First, you can factor it:

x^2-x=x(x-1).

Since x is integer number, then you can see that x-1 is previous integer number (x-1 is 1 unit smaller than x).

Therefore, x-1 and x are two consecutive integers. When you have two consecutive integers, one of them is always even and one is always odd. Multiplying even integer number by odd integer number you always get even integer number.

Thus, x^2-x is always even.

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3 years ago
Can you help me, please?
NemiM [27]

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8 0
2 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
The sweet sweet shop charges $8.45 for a pound of chocolate covered almonds. If Britain buys 1.5 pounds of the almonds, how much
choli [55]

Answer:

$12.68

Step-by-step explanation:

Multiply the price of one pound by the amount of pounds you're buying,

8.45 x 1.5

= 12.675

Round up

= 12.68

5 0
3 years ago
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