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8_murik_8 [283]
3 years ago
8

Twelve ping-pong balls are in a bag. Ten are white and two are orange. Find the probability that the two orange ping-pong balls

are chosen without replacement and name the type of event. *​
Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

2/12 of a probability

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A scale diagram of a statue is drawn using a scale of 1 cm to 6 m.
barxatty [35]

Answer:

5cm in the diagram

Step-by-step explanation:

30/6=5

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The angle of STV would be 140 degrees.
3 0
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y = c1 cos(5x) + c2 sin(5x) is a two-parameter family of solutions of the second-order DE y'' + 25y = 0. If possible, find a sol
TEA [102]

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

3 0
3 years ago
Swimming 1/4 of a mile uses about the same number of calories as running 1 mile. Glida ran a 26 mile marathon. about how far wou
natulia [17]

Answer:

6.5 miles

Step-by-step explanation:

26/4=6.5 miles

1/4 of a mile per every mile so just divide each mile by 4

7 0
3 years ago
The graph of f passes through (-6,9) and is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24 the
Valentin [98]

Given:

The graph of f passes through (-6,9).

It is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24.

To find:

The equation of the function f.

Solution:

The equation of line on which graph of f is perpendicular, is

\dfrac{x}{a}+\dfrac{y}{b}=1

where, a and b are x and y intercepts respectively.

\dfrac{x}{8}+\dfrac{y}{-24}=1

Multiply both sides by 24.

3x-y=24

Slope intercept form is

y=3x-24

Slope of this line is 3 and y-intercept is -24.

Product of slopes of two perpendicular lines is -1.

Let the slope of f is m. So,

m\times 3=-1

m=-\dfrac{1}{3}

Slope of m is -1/3 and it passes through (-6,9). So, the equation of function f is

y-y_1=m(x-x_1)

y-9=-\dfrac{1}{3}(x-(-6))

y-9=-\dfrac{1}{3}(x+6)

y-9=-\dfrac{1}{3}x-2

y=-\dfrac{1}{3}x-2+9

y=-\dfrac{1}{3}x+7

Put y=f(x).

f(x)=-\dfrac{1}{3}x+7

Therefore, the required function is f(x)=-\dfrac{1}{3}x+7.

7 0
3 years ago
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