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hjlf
2 years ago
15

$49.95 gloves 5 1/4 % markup

Mathematics
1 answer:
andreev551 [17]2 years ago
5 0

Answer:

1234567891011121314151617181920

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Rewrite the product as a sum: 10cos(5x)sin(10x)
mote1985 [20]

Answer:

10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

Step-by-step explanation:

In this question, we are tasked with writing the product as a sum.

To do this, we shall be using the sum to product formula below;

cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]

From the question, we can say α= 5x and β= 10x

Plugging these values into the equation, we have

10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]

= 5[sin (15x) - sin (-5x)]

We apply odd identity i.e sin(-x) = -sinx

Thus applying same to sin(-5x)

sin(-5x) = -sin(5x)

Thus;

5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]

= 5[sin (15x) + sin (5x)]

Hence,  10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

8 0
3 years ago
The
stiv31 [10]

Answer:

x = -3. Y = 12

Step-by-step explanation:

the answer is D

6 0
3 years ago
Which of the following statements is true of an essay's conclusion?
laiz [17]
The answer is option D.
8 0
3 years ago
Please answer the question ​
Lady bird [3.3K]

Answer:

the first one is

+2 +4 + 8 + 16 +32

he multiply by 2 every time he add numbers so its 65

the second one he make this

-8 -4 -2 -1

every time he Take from numbers he devide by 2

so its 5

the third one

+6 +18 + 54 + 162

every time he add he multiply by 3

ao its 162 +80 =242

the fourth one is

+33 +66 + 132 +264

he multiply by 2 every time he add

so its 267+264=531

the fiveth one is

he put the roots

2²,3²,4²,5²,6²

so the answer is 36

Step-by-step explanation:

A 65

B 5

C 242

D 531

E 36

hopefully its helpful man

6 0
2 years ago
You want to test the effect of light on the distribution of Artemia in your 35cm long testing chamber. If you measure the light
Dvinal [7]

Answer:

64.3 lumens

Step-by-step explanation:

Data provided in the question:

Length of the testing chamber = 35 cm

Light at one end = 10 lumens

Light at other end = 200 lumens

now,

since the variation is linear,

therefore, the gradient of the variation

= \frac{200-10}{35}

= 5.43

also,

the darkest end is the end with 10 lumens

therefore,

The lumens at 10 cm from the darkest end

= 10 + 5.43(10)

= 10 + 54.3

= 64.3 lumens

6 0
3 years ago
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