Since Porter is taller than Henry, we'll subtract away Henry's height from Porter's height. This will leave us with only the difference between the heights.

n = Porter's height

m = Henry's height

Difference in height is thus:

$n-m$

Answer: Porter is $n-m$ inches taller than Henry.

To find out how many times taller Porter is than Henry, we can use division.

An example: if Porter was 200cm, and Henry was 100cm, Porter is obviously 2 times as tall.

If we divide Porter's height by Henry's height...

$\frac{200}{100}=2$

..we'll get 2. This is because Henry's height "fits in twice" in Porter's height. 100 fits twice in 200.

Using our values, n and m, we'll divide n by m.

$\frac{n}{m}$

Answer: Porter is $\frac{n}{m}$ times taller than henry.

3 0

3 years ago

PLEASE HELP ME IF YOU CAN! please tell me how you got the answer thank you!

Temka [501]

3sqrt(2)

You can either use Pythagorean theorem or special triangle proportions to find the side that is parallel to z. Since in a 45-45-90 degree triangle, the hypotenuse is the leg times the square root of 2, and the hypotenuse is 3, we know that the leg is 3/sqrt(2) which is equal to 3 sqrt(2) / 2. Since z is twice this length, we know that z is equal to 2 x 3sqrt(2)/2 = 3sqrt(2)

3 0

3 years ago