<h2>Steps</h2>
So here are a couple expressions when a value changes by percentage (p = percentage in decimal form and m = original value):
- When <em>decrease</em>: (1 - p)m
- When <em>increase</em>: (1 + p)m
So firstly, the $80 share dropped by 15%. Since this is a <em>decrease</em>, follow the appropriate expression:

<em>On Tuesday, the share went from $80 to $68</em>
Next, on Wednesday the share increased by $7. With this, just add $68 and 7.

<em>On Wednesday, the share went from $68 to $75</em>
Lastly, on Thursday the share increased by 12%. Since this is an <em>increase</em>, follow the appropriate expression:

<h2>Answer</h2>
<u>The final price of the share is $84.</u>
Answer:
x (blue circle thing) = 46
y (dna) = -63
z (molecules) = 52
Step-by-step explanation:
1/4 , 1/2 , 2/3 , 5/6
I hope I helped you with your question
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer
Cameron forgot to do the same thing to the 9. Instead of dividing 3 by 3 and 9 by 3 he only divided 3 by 3.
Step-by-step explanation:
3/7 × 4/9
You can divide the 3 and 9 by 3 so you get 1/7 × 4/3.
Then you do 4 × 1 and 7 × 3.
Correct answer is 4/21