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Gennadij [26K]
3 years ago
11

:3 Help in math, please? I will give you a cookie.

Mathematics
1 answer:
den301095 [7]3 years ago
4 0
Y=5-3x
5x-4y=-3

y=5-3x
-4y=-3-5x
----------------
-3y=2-7x


-3(y)=2-7(x)
u can try plugging in any number for y

-3(3)=2-7x
9=2-7x
-2 -2
7=7x
-- --
7 7
1=x

so 3,1
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An abolitionist supports which of the following causes?
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Ending slavery and ending women sufferage
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3 years ago
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State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
Pls help me prove this
Levart [38]

Parallel lines

Lines that are always at a given distance from each other and never cross, is called the "parallel" line.

If a diagonal line (PS) interrupts two parallel lines and gives them equal angles, can say that these two lines are parallel. Because the angles are opposite to the vertex and has it opposite angles with other angle

Sorry i can not say this, Because the educational system is different


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3 years ago
Three people chipped in to buy lottery tickets. Mark contributed $3 per week, Martha contributed $3 per week, and Mario contribu
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Answer:

2500

Step-by-step explanation:

7500 / 3

dunno if this correct you can do more math in calculator if incorrect.

I wish you the best!

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90 minutes because 20 + 20 + 20 + 20 + 10 = 90
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3 years ago
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