The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
this is ur answer i hope u do well good luck:
If A and B are complementary angles, then they add up to 90 degrees.
So A + B = 90 => (x + 24) + (x + 16) = 90 => 2x + 40 = 90 => 2x = 50.
So x = 25, and thus, the measurement of B is (25 + 16) = 41.
The measurement of angle A is (25 + 24) = 49, and indeed they are complementary.
<h3>
Answer: 48 degrees</h3>
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Work Shown:
Apply the law of cosines
a^2 = b^2 + c^2 - 2*b*c*cos(A)
10^2 = 13^2 + 11^2 - 2*13*11*cos(A)
100 = 290 - 286*cos(A)
100-290 = -286*cos(A)
-190 = -286*cos(A)
190 = 286*cos(A)
286*cos(A) = 190
cos(A) = 190/286
A = arccos(190/286)
A = 48.368620460647
A = 48
Make sure your calculator is in degree mode.
