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2 years ago

3) How many whole 3s are there inside of 4½?

Mathematics

2 answers:

tankabanditka [31]2 years ago

5 0

Answer:

Step-by-step explanation:

There is one whole 3 inside of 4 1/2 or 4.5.

Multiples of 3 are 3x1=3 3x2=6....

Only a single whole 3 can be inside of 4.5.

Vsevolod [243]2 years ago

4 0

Answer:

One

Step-by-step explanation:

ONE

4.5 ÷ 3 = 1 . 5 <=====so there is one and a half 3's in 4.5

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What is 4p-13p-p=-150 More 2 step equations. I don't get this one at all

raketka [301]

4p-13p-p=-150
-9p-p=-150
-10p=-150
p=15
Order of operations. Doing so turns it into a simple division equation.

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3 years ago

Read 2 more answers

Does it matter what order you add the numbers in the problem

EastWind [94]

Answer:no it doesn’t matter what order you add the number.

Step-by-step explanation:

2 plus 3 equals 5

3 plus 2 equals 5

No matter the way you add 3 and 2, you still get 5

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3 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

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3 years ago

"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim

iren [92.7K]

Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

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3 years ago

n ΔABC, if the length of sides a, b, and c are 3.5 centimeters, 5.5 centimeters, and 6 centimeters respectively, what is m∠C to

borishaifa [10]

We are given with three sides with measurements such as below:
a = 3.5 cm
b = 5.5 cm
c = 6 cm
We are asked to solve for m∠C. To solve this we need to apply Law of Cosines such as below:
cos C = a²+b² - c² /2ab
cos C = 3.5² + 5.5² -6² / (2*3.5*5.5)
cos C = 0.16883
C = 80.28°

7 0

3 years ago