It’s 15 percent to be honest I suvj at math and just need points for help I’m sorry
Use a special metho I forgot who made it
do the division using paper and long division
steps:
1. pick an estimate of the square root
example, if we find sqrt of 5, if we pick 2
2. divide the number by the estimate,
example, 5/2=2.5
3. average the result and the estimate
example, average of 2 and 2.5 is 2.25
4. repeat steps 1 to 3 with the number from step 3 as the estimate
example, 5/2.25=2.22222222, average is 2.236111, repeat previous steps
Answer:
![\large\boxed{(f+g)(x)=x^2+3x-3}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28f%2Bg%29%28x%29%3Dx%5E2%2B3x-3%7D)
Step-by-step explanation:
![(f+g)(x)=f(x)+g(x)\\\\f(x)=3x-5,\ g(x)=x^2+2\\\\\text{Substitute:}\\\\(f+g)(x)=(3x-5)+(x^2+2)=3x-5+x^2+2=x^2+3x+(-5+2)=x^2+3x-3](https://tex.z-dn.net/?f=%28f%2Bg%29%28x%29%3Df%28x%29%2Bg%28x%29%5C%5C%5C%5Cf%28x%29%3D3x-5%2C%5C%20g%28x%29%3Dx%5E2%2B2%5C%5C%5C%5C%5Ctext%7BSubstitute%3A%7D%5C%5C%5C%5C%28f%2Bg%29%28x%29%3D%283x-5%29%2B%28x%5E2%2B2%29%3D3x-5%2Bx%5E2%2B2%3Dx%5E2%2B3x%2B%28-5%2B2%29%3Dx%5E2%2B3x-3)
Answer:
The answer is 7.25. That is there will be no change.
Step-by-step explanation:
The equations of differential vector transformation from the v-u plane to the x-y plane is given by,
![\left[\begin{array}{ccc}dx\\dy\end{array}\right] = \left[\begin{array}{ccc}dx/dv&dx/du\\dy/dv&dy/du\end{array}\right] \left[\begin{array}{ccc}dv\\du\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Ddx%5C%5Cdy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Ddx%2Fdv%26dx%2Fdu%5C%5Cdy%2Fdv%26dy%2Fdu%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Ddv%5C%5Cdu%5Cend%7Barray%7D%5Cright%5D)
where the square matrix given is the Jacobian matrix and we can evaluate it by differentiating the equation for x and y given in the question by v and u and we will obtain the following matrix,
.
Differential area transformation from v-u coordinate system to the x-y coordinate systen is given by,
![dxdy = Det(J)dvdu](https://tex.z-dn.net/?f=dxdy%20%3D%20Det%28J%29dvdu)
where Det(J), is evaluated as below,
![Det(J) = (-4)*(-4) - (-3)*(-5) = 1](https://tex.z-dn.net/?f=Det%28J%29%20%3D%20%28-4%29%2A%28-4%29%20-%20%28-3%29%2A%28-5%29%20%3D%201)
which we plug into the above equation to obtain,
![dxdy = dvdu](https://tex.z-dn.net/?f=dxdy%20%3D%20dvdu)
in part b) area of the region D in the u-v plane is given as 7.25 that is dvdu=7.25 , that means according to the above equation that the area of the corresponding transformed region in the x-y plane that is dxdy will also be the same according o the above equation,So,
![Area T(D) = dxdy = dvdu =Area D= 7.25](https://tex.z-dn.net/?f=Area%20T%28D%29%20%3D%20dxdy%20%3D%20dvdu%20%3DArea%20D%3D%207.25)
I think its the third one but im not 100% posative on that