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lianna [129]
3 years ago
7

The area of a rectangle is 27ft^2, and the length of the rectangle is 3ft less than twice the width. find the dimensions of the

rectangle.
Mathematics
1 answer:
Elanso [62]3 years ago
3 0
The answer is 4.5.

The formula for a rectangle is A = lw. Substitute the formula, so it'll be 27 = (2x - 3) * x. Evaluate the formula.

Hope this helps you! And rate me to see if I did it right. Thanks!
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A pound of chocolate costs 8 dollars. Kelsha buys p pounds. Write an equation to represent the total cost c that Keisha pays.
mote1985 [20]

The equation would be 8 times the amount of pounds bought equals the amount paid.

<h2>Answer:</h2>

8p = c

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Determine whether the statement is always, sometimes, or never true: Two points A and B determine a line. *
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Step-by-step explanation:

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Over what interval will the immediate value theorem apply
koban [17]

Answer:

Any [a,b] that does NOT include the x-value 3 in it.

Either an [a,b] entirely to the left of 3, or

an  [a,b] entirely to the right of 3

Step-by-step explanation:

The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.

Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.

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Absolute value inequalities. 10-4|9y-10|&lt;-94
Ivahew [28]

Answer: \begin{bmatrix}\mathrm{Solution:}\:&\:y4\:\\ \:\mathrm{Decimal:}&\:y4\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-\frac{16}{9}\right)\cup \left(4,\:\infty \:\right)\end{bmatrix}

Step-by-step explanation:

10-4\left|9y-10\right|

10-4\left|9y-10\right|-10

-4\left|9y-10\right|

\left(-4\left|9y-10\right|\right)\left(-1\right)>\left(-104\right)\left(-1\right)

4\left|9y-10\right|>104

\frac{4\left|9y-10\right|}{4}>\frac{104}{4}

\left|9y-10\right|>26

9y-1026

y4

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3 years ago
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