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sesenic [268]
3 years ago
9

What is −15 ÷ 3/5? −25 −9 −19 −125

Mathematics
2 answers:
MAXImum [283]3 years ago
5 0

Answer:

-25, or a

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago
3 0
Your answer would like 1) -25
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PLEASE HELP ME, LIKE ACTUALLY! The sum of two numbers is 193. One of them in 71 more than the other. Find the larger of these tw
3241004551 [841]

Answer:

132

Step-by-step explanation:

X is smaller number

x + 71 is larger number.

x+ (x+71)=193

2x = 193-71

2x=122

x=61

x+71=largest number

61+71=132 largest numher

check answer

x+(x+71)=193

61+132=193

5 0
3 years ago
Read 2 more answers
9. If y varies directly with x and y = -3 when x = 6, find y when x = 14.
masya89 [10]

9)

If y varies directly with x and y = -3 when x = 6, find y when x = 14.

We know if y varies directly with x, we get the equation

y ∝ x

y = kx

k = y/x

where k is called the constant of variation.

we are given y = -3 when x = 6

so substitute y = -3 and x = 6 to determine 'k'

k = y/x

k = -3/6 = -1/2

Now we have to find y when x = 14

so substituting x = 14 and k = -1/2 to find y

y = kx

y =  -1/2 × 14 = -7

Therefore, the value of y = -7 when x = 14

10) If y is directly proportional to x and y = 4 when x = 3, find x when y = -12.

we are given y = 4 when x = 3

so substitute y = 4 and x = 3 to determine 'k'

k = y/x

k = 4/3

Now we have to find x when y = -12

so substituting y = -12 and k = 4/3 to find x

y = kx

x = y/k

x = [-12] / [4/3] = [-12×3] / [4]

x = -36/4

x = -9

Therefore, the value of x = -9 when x = 3

11)

If y varies directly with x and y = -6 when x = 2, find the constant of variation.

We are given

y = -6

x = 2

so substitute y = -6 and x = 2 in the equation

k = y/x

k = -6/2

k = -3

Therefore, the value of the constant of variation will be:

  • k = -3
7 0
3 years ago
Janelle has 75$. She buys jeans that are on sale for half the price and then uses an In store coupon for 10$ off. After paying $
Nadya [2.5K]
I think that the answer is $92
6 0
3 years ago
Which of the following sets of numbers could be the lengths of the sides of a triangle?
dimulka [17.4K]
The sum of the lengths of two shorter sides of a triangle must be greater than the length of the longest side.

A. \\
8+8\ \textgreater \ 17 \\
16\ \textgreater \ 17 \\ 
false \\ \\
B. \\
2+4\ \textgreater \ 8 \\
6\ \textgreater \ 8 \\
false \\ \\
C. \\
8+16\ \textgreater \ 24 \\
24\ \textgreater \ 24 \\
false \\ \\
D. \\
4+6\ \textgreater \ 8 \\
10\ \textgreater \ 8 \\
true

The answer is D.
5 0
3 years ago
Read 2 more answers
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

8 0
3 years ago
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