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3 years ago

Two fractions have a common denominators of 8. What could the two fractions be?

2 answers:

4 0

The denominator is the bottom number so the answer can be any of 1/8 3/8 5/8 7/8

I made the numerator an odd number because an even number would reduce.

Anna71 [15]3 years ago

3 0

4 and 8 would be the anwser because 4 x 2 = 8 and then 8x1=8

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A rectangle an area of 52 square feet .the length is 9 feet longer than the width. What equation could use to represent this ?

TEA [102]

Answer:

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Step-by-step explanation:

5 0

3 years ago

Find the GCF of the following set of numbers 260, 80, 50

Vinvika [58]

Answer:

Step-by-step explanation:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factors of 260 are: 1, 2, 4, 5, 10, 13, 20, 26, 52, 65, 130, 260

In all of these numbers, we can see that 10 is common throughout and 10 is also the greatest factor all these numbers share.

Hope this helps you :)

7 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the points (-2, -5) and (-1, 1)?

Dennis_Churaev [7]

Answer: y=6x+7

Step-by-step explanation:

To find the equation of the line, we want to find the slope with the formula $m=\frac{y_2-y_1}{x_2-x_1}$ .

$m=\frac{1-(-5)}{-1-(-2)} =\frac{6}{1}=6$

Now that we know th eslope, we can start to fill out the equation. To find the y-intercept, we can plug in a given point and solve.

y=6x+b

1=6(-1)+b [multiply]

1=-6+b [add both sides by 6]

b=7

Now, we know the equation is y=6x+7.

8 0

3 years ago

Read 2 more answers

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$